请用python编写一个五子棋程序？

好的，以下是一个简单的五子棋程序的 Python 代码：

import numpy as np

# 定义棋盘大小
BOARD_SIZE = 15

# 定义棋子种类
EMPTY = 0
BLACK = 1
WHITE = 2

# 定义胜利条件
WIN_COUNT = 5

# 初始化棋盘
board = np.zeros((BOARD_SIZE, BOARD_SIZE), dtype=int)

# 定义落子函数
def make_move(player, row, col):
    board[row][col] = player

# 定义判断胜利函数
def check_win(player):
    # 检查行
    for row in range(BOARD_SIZE):
        for col in range(BOARD_SIZE - WIN_COUNT + 1):
            if all(board[row][col+i] == player for i in range(WIN_COUNT)):
                return True
    # 检查列
    for col in range(BOARD_SIZE):
        for row in range(BOARD_SIZE - WIN_COUNT + 1):
            if all(board[row+i][col] == player for i in range(WIN_COUNT)):
                return True
    # 检查正对角线
    for row in range(BOARD_SIZE - WIN_COUNT + 1):
        for col in range(BOARD_SIZE - WIN_COUNT + 1):
            if all(board[row+i][col+i] == player for i in range(WIN_COUNT)):
                return True
    # 检查反对角线
    for row in range(WIN_COUNT - 1, BOARD_SIZE):
        for col in range(BOARD_SIZE - WIN_COUNT + 1):
            if all(board[row-i][col+i] == player for i in range(WIN_COUNT)):
                return True
    return False

# 定义主函数
def main():
    # 初始化玩家和游戏状态
    player = BLACK
    game_over = False
    # 游戏循环
    while not game_over:
        # 打印棋盘
        print(board)
        # 玩家落子
        row = int(input("Enter row: "))
        col = int(input("Enter col: "))
        make_move(player, row, col)
        # 判断胜利
        if check_win(player):
            print("Player", player, "wins!")
            game_over = True
        # 切换玩家
        player = WHITE if player == BLACK else BLACK

# 运行主函数
if __name__ == '__main__':
    main()

这个程序使用了 NumPy 库来创建和操作二维数组，可以在命令行中输入行号和列号来落子。注意这个程序只是一个简单的演示，没有考虑很多棋局中的特殊情况，比如禁手等。