写一段51单片机8个数码管从左往右滚动显示1、9、8、6、3、4、8、9的代码

以下是基于51单片机的8051架构的代码，实现8个数码管从左往右滚动显示1、9、8、6、3、4、8、9：

#include <reg51.h>

// 数码管的连接方式
sbit dig1 = P1^0;
sbit dig2 = P1^1;
sbit dig3 = P1^2;
sbit dig4 = P1^3;
sbit dig5 = P1^4;
sbit dig6 = P1^5;
sbit dig7 = P1^6;
sbit dig8 = P1^7;

// 数码管对应数字的编码
unsigned char code table[] = {
    0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, 0x80, 0x90
};

void delay(unsigned int x) {
    unsigned int i, j;
    for (i = x; i > 0; i--)
        for (j = 110; j > 0; j--);
}

void main() {
    unsigned char i, j;
    unsigned char data[] = {1, 9, 8, 6, 3, 4, 8, 9}; // 要显示的数字
    while (1) {
        // 从左往右滚动
        for (i = 0; i < 8; i++) {
            dig1 = 1; dig2 = 0; dig3 = 0; dig4 = 0;
            dig5 = 0; dig6 = 0; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 0) % 8]];
            delay(1);
            dig1 = 0; dig2 = 1; dig3 = 0; dig4 = 0;
            dig5 = 0; dig6 = 0; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 1) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 1; dig4 = 0;
            dig5 = 0; dig6 = 0; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 2) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 0; dig4 = 1;
            dig5 = 0; dig6 = 0; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 3) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 0; dig4 = 0;
            dig5 = 1; dig6 = 0; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 4) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 0; dig4 = 0;
            dig5 = 0; dig6 = 1; dig7 = 0; dig8 = 0;
            P0 = table[data[(i + 5) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 0; dig4 = 0;
            dig5 = 0; dig6 = 0; dig7 = 1; dig8 = 0;
            P0 = table[data[(i + 6) % 8]];
            delay(1);
            dig1 = 0; dig2 = 0; dig3 = 0; dig4 = 0;
            dig5 = 0; dig6 = 0; dig7 = 0; dig8 = 1;
            P0 = table[data[(i + 7) % 8]];
            delay(1);
        }
    }
}