.text addi $t1,$zero,0 #init_addr addi $t3,$zero,32 #counter #sb写入 01,02,03,04 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,($t1) add $a0,$zero,$s1 addi $v0,$zero,34 # system call for print syscall # print add $s1,$s1,$s2 #data +1 addi $t1,$t1,1 # addr ++ addi $t3,$t3,-1 #counter bne $t3,$zero,sb_store addi $t3,$zero,8 addi $t1,$zero,0 # addr sb_branch: lw $s1,($t1) #读出数据 add $a0,$zero,$s1 addi $v0,$zero,34 # system call for print syscall # print addi $t1,$t1,4 addi $t3,$t3, -1 bne $t3,$zero,sb_branch addi $v0,$zero,10 # system call for exit syscall # we are out of here. 修改这段代码使之依次输出 0x00000000 0x00000001 0x00000002 0x00000003 0x00000004 0x00000005 0x00000006 0x00000007 0x00000008 0x00000009 0x0000000a 0x0000000b 0x0000000c 0x0000000d 0x0000000e 0x0000000f 0x00000010 0x00000011 0x00000012 0x00000013 0x00000014 0x00000015 0x00000016 0x00000017 0x00000018 0x00000019 0x0000001a 0x0000001b 0x0000001c 0x0000001d 0x0000001e 0x0000001f 0x03020100 0x07060504 0x0b0a0908 0x0f0e0d0c 0x13121110 0x17161514 0x1b1a1918 0x1f1e1d1c 并说明原因

用中文依次解释每一句的意思.text addi $t1,$zero,0 #init_addr addi $t3,$zero,32 #counter #sb写入 01,02,03,04 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,-100($t1) add $a0,$0,$s1 addi $v0,$zero,34

- addi $t3, $zero, 32：将寄存器 $t3 的值设置为 32，用于计数器 - addi $s1, $zero, 0x00：将寄存器 $s1 的值设置为 0x00，用于写入内存地址 - addi $s2, $zero, 0x01：将寄存器 $s2 的值设置为 0x01，用于增加...

.text addi $t1,$zero,0 #init_addr addi $t3,$zero,32 #counter #sb写入 00,01,02,03,04,05,06,07 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,($t1) add $a0,$zero,$s1 addi $v0,$zero,34 # system call for print syscall # print add $s1,$s1,$s2 #data +1 addi $t1,$t1,1 # addr ++ addi $t3,$t3,-1 #counter bne $t3,$zero,sb_store #sb写入 08,09,0a,0b,0c,0d,0e,0f addi $s1,$zero, 0x08 # addi $s2,$zero, 0x01 # sb_store2: sb $s1,($t1) add $a0,$zero,$s1 addi $v0,$zero,34 # system call for print syscall # print add $s1,$s1,$s2 #data +1 addi $t1,$t1,1 # addr ++ addi $t3,$t3,-1 #counter bne $t3,$zero,sb_store2 #lw读取并输出 addi $t3,$zero,16 addi $t1,$zero,0 # addr sb_branch: lw $s1,($t1) #读出数据 add $a0,$zero,$s1 addi $v0,$zero,34 # system call for print syscall # print addi $t1,$t1,4 # addr += 4 addi $t3,$t3,-1 #counter bne $t3,$zero,sb_branch addi $v0,$zero,10 # system call for exit syscall # we are out of here. 逐行解释上面每段代码的含义，并解释mips运行步骤

然后，程序进入另一个循环，使用 sb 指令将 $s1 中的值写入到 $t1 指向的内存地址中，并不断更新 $s1 和 $t1 的值，直到计数器的值为0，这次写入的数据是 08,09,0a,0b,0c,0d,0e,0f。最后，程序又进入一个循环，...

addi $t1,$zero,0 #init_addr addi $t3,$zero,32 #counter #sb写入 01,02,03,04 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,($t1) add $a0,$0,$s1 addi $v0,$zero,34 # system call for print syscall # print add $s1,$s1,$s2 #data +1 addi $t1,$t1,1 # addr ++ addi $t3,$t3,-1 #counter bne $t3,$zero,sb_store addi $t3,$zero,8 addi $t1,$zero,0 # addr sb_branch: lw $s1,($t1) #读出数据 add $a0,$0,$s1 addi $v0,$zero,34 # system call for print syscall # print addi $t1,$t1,4 addi $t3,$t3, -1 bne $t3,$zero,sb_branch addi $v0,$zero,10 # system call for exit syscall # we are out of here. 以上代码有错误，请修改

addi $t1, $zero, 0 # 初始化地址 addi $t3, $zero, 4 # 计数器 # 写入数据 0x01, 0x02, 0x03, 0x04 addi $s1, $zero, 0x01 # 数据 0x01 sb $s1, ($t1) # 存储数据到地址 t1 addi $t1, $t1, 1 # 地址 +1 addi $s1, ...

改正代码.text addi $t1,$zero,0 addi $t3,$zero,32 #sb写入 01,02,03,04 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,($t1) add $a0,$0,$s1 addi $v0,$zero,34 syscall add $s1,$s1,$s2 addi $t1,$t1,1 addi $t3,$t3,-1 bne $t3,$zero,sb_store addi $t3,$zero,8 addi $t1,$zero,0 sb_branch: lw $s1,($t1) add $a0,$0,$s1 addi $v0,$zero,34 syscall addi $t1,$t1,4 addi $t3,$t3, -1 bne $t3,$zero,sb_branch addi $v0,$zero,10 # system call for exit syscall 使其输出到0x1f1e1d1c

# sb写入 01,02,03,04 addi $s1, $zero, 0x00 addi $s2, $zero, 0x01 sb_store: sb $s1, ($t1) add $a0, $zero, $s1 addi $v0, $zero, 34 addi $a1, $zero, 0x1f1e1d1c syscall add $s1, $s1, $s2 addi $t1,...

addi $t1, $zero, 0addi $t3, $zero, 32# sb写入 01,02,03,04addi $s1, $zero, 0x00addi $s2, $zero, 0x01sb_store: sb $s1, ($t1) add $a0, $zero, $s1 addi $v0, $zero, 34 addi $a1, $zero, 0x1f1e1d1c syscall add $s1, $s1, $s2 addi $t1, $t1, 1 addi $t3, $t3, -1 bne $t3, $zero, sb_storeaddi $t3, $zero, 8addi $t1, $zero, 0sb_branch: lw $s1, ($t1) add $a0, $zero, $s1 addi $v0, $zero, 34 addi $a1, $zero, 0x1f1e1d1c syscall addi $t1, $t1, 4 addi $t3, $t3, -1 bne $t3, $zero, sb_branchaddi $v0, $zero, 10syscall 请在输出的每个数字后加空格

# sb写入 01,02,03,04 addi $s1, $zero, 0x00 addi $s2, $zero, 0x01 sb_store: sb $s1, ($t1) add $a0, $zero, $s1 addi $v0, $zero, 34 addi $a1, $zero, 0x1f1e1d1c syscall add $s1, $s1, $s2 addi $t1...

在MARS 4.5中运行以下代码：addi $a0 $zero 5 # x = 5 lui $t0 0x4000 addi $t0 $t0 0 # $t0 = address of reg_op sw $a0 0($t0) # set reg_op = 5 lui $t1 0x4000 addi $t1 $t0 8 # $t1 = address of reg_start addi $a1 $zero 1 # $a1 = 1 sw $a1 0($t1) # set reg_start = 1 addi $a0 $zero 7 # y = 7 jal h_y # calc y^2 + y addi $s1 $v0 0 # $s1 = h(y) lui $t2 0x4000 addi $t2 $t2 4 # $t2 = address of reg_ans lw $s0 0($t2) # $s0 = g(x) sub $s2 $s0 $s1 # $s2 = f(x, y) loop: j loop h_y: add $t0 $zero $a0 # partial sum $t0 = y mul $t1 $a0 $a0 # $t1 = y^2 add $t0 $t0 $t1 # $t0 = y + y^2 addi $v0 $t0 0 # $v0 = $t0 jr $ra # return h(y)会报错显示：Runtime exception at 0x0040000c: address out of range 0x40000000，应该怎样修改代码

addi $v0, $t0, 0 # $v0 = $t0 jr $ra # return h(y) .data reg_op: .word 0 # global variable reg_op reg_start: .word 0 # global variable reg_start reg_ans: .word 0 # global variable reg_ans 在...

.data A:.word 10, 20, 50, -2, 8, -8, 34, -35, 80, -19 n:.word 0 t:.word 0 .globl main swap: add $sp, $sp, -4 # 保存现场 sw $ra, 0($sp) lw $t2, 0($a0) li $v0,0 lw $t3, 0($a1) # 加载x和y到$t2和$t3 ble $t2, $t3, swap_exit # 如果x > y，则交换它们 sw $t3, 0($a0) sw $t2, 0($a1) addi $v0, $zero, 1 # 返回1 j swap_exit# 恢复现场 swap_exit: lw $ra, 0($sp) addi $sp, $sp, 4 jr $ra main: # 初始化i和n li $t0, 0 # $t0 = i = 0 sw $t0, n # n = 0 outer_loop: # 初始化j addi $t1, $t0, 1 # $t1 = j = i + 1 inner_loop: la $t4,A sll $t8,$t0,2 sll $t9,$t1,2 #逻辑左移，找到数组内地址 la $a0,$t8($t4) #$t4=A[0]地址 la $a1,$t9($t4) jal swap # 调用swap函数 add $s0, $zero, $v0 # $s0 = swap的返回值 # 如果swap返回1，则交换a[i]和a[j] bne $s0, 1, swap_done j swap_skip swap_done: lw $t3,n addi $t3,$t3,1 sw $t3,n swap_skip: addi $t1, $t1, 1 # 更新j blt $t1, 10, inner_loop # 如果j < 10，则继续内层循环 addi $t0, $t0, 1 # 更新i blt $t0, 9, outer_loop # 如果i < 9，则继续外层循环 lw $a0, n # 输出n li $v0, 1 syscall li $v0, 10 syscall那有错误

外层循环迭代i从0到8，内层循环迭代j从i + 1到9。在每次迭代中，它比较A[i]和A[j]的值，如果A[i]比A[j]大，则调用swap函数交换它们。如果swap函数返回1，它会更新一个计数器n。最后，程序输出n的值，即交换次数。

将以下函数翻译成c++语言CreatePrimes: la $a1,prime #把数组首地址存放到a1 li $t7,3 #数组第一个数设置为3 sh $t7,0($a1) #半字存储 addi $a1,$a1,2 #地址偏移加2 li $t1,5 #定义变量i，赋初值5 li $t2,1 #定义变量j，赋初值1 li $t3,65536 #初始化循环计数 loop: #外层循环 li $t4,3 #定义变量k loop2: #内层循环 divu $t1,$t4 #判断能否整除 mfhi $t0 #将余数移入 beqz $t0,loop3 #第一个if判断 mul $t5,$t4,$t4 #计算循环计数kk，存入t5 addi $t4,$t4,2 #变量k累计加2 ble $t5,$t1,loop2 #判断kk是否小于等于i loop3: move $t7,$t4 #这里注意要重新设置一个判断数，因为t5里的值可能用不到 mul $t8,$t7,$t7 #相当与k*k ble $t8,$t1,else #第二个if判断？？？ sh $t1,0($a1) #半字存入 addi $t2,$t2,1 #个数累加 addi $a1,$a1,2 #地址累加 else: addi $t1,$t1,2 blt $t1,65536,loop print: subi $t1,$t2,10 #设置循环变量 la $t3,prime #将数组地址赋值给t3 mul $t7,$t1,2 #因为以2字节存储，所以要将个数存入 add $t3,$t3,$t7 #地址量偏移 li $v0,1 move $a0,$t2 #打印素数个数 syscall li $v0,4 #打印提示字符串 la $a0,out_1 syscall loop4: li $v0,1 #调用打印整数的系统接口 lhu $a0,($t3) #将指针所指向的数移入$a0 syscall li $v0,4 #调用打印字符串的系统接口 la $a0,nps syscall addi $t1,$t1,1 #个数递增1 addi $t3,$t3,2 #地址递增2 blt $t1,$t2,loop4 #如果小于的话继续循环 li $v0,4 #打印字符串 la $a0,table syscall move $a0,$t2 #将素数个数通过寄存器$a0返回 jr $ra #返回主函数

int t1 = 5; int t2 = 1; int t3 = 65536; for (int i = 0; i < t3; i++) { int t4 = 3; while (true) { int t0; divu(t1, t4); mfhi(t0); if (t0 == 0) { break; } int t5 = t4 * t4; t4 += 2; if ...

在MIPS中，下面四个指令错误的是：A.add $t1,$t1,$t1 B.sub $t1,$t1,$t1 C.addi $t1,$t1,100 D.subi $t1,$t1,100

指令B.sub $t1,$t1,$t1的操作是将$t1中的值减去$t1中的值，结果肯定为0，没有意义。指令D.subi $t1,$t1,100的操作是将$t1中的值减去一个立即数100，如果结果小于-2^31或大于等于2^31，则会发生算术溢出。因此，这两...

#array.asm .data A: .word 0,0,0,0,0 B: .word 1,2,3,4,5 C: .word 10 str: .byte ';',0 .text main: lw $t1,C #$t1=C li $t2,0 #$t2=i la $s1, B #送B数组的首地址到$s1 la $s2, A #送B数组的首地址到$s2 again: bge $t2,5,done #$t2>=5跳转到done lw $t3,($s1) add $t4,$t3,$t1 sw $t4,($s2) addi $s1,$s1,4 addi $s2,$s2,4 addi $t2,$t2,1 li $v0,1 #1号调用显示A[i]的值 add $a0,$t4,$zero syscall li $v0,4 #4号调用显示";"的值 la $a0,str syscall j again done: li $v0,10 syscall解释一下

在循环中，每次使用了 lw 指令将数组 B 中的值加载到寄存器 $t3 中，使用了 add 指令将 $t3 和 $t1 相加得到结果存储到寄存器 $t4 中，使用了 sw（store word）指令将 $t4 中的值存储到数组 A 中，使用了 addi 指令...

addi $s0, $zero,10 addi $s1, $zero, 3 addi $s2, $zero, 5 addi $s3, $zero,6 addi $s4, $zero,6 bne $s3, $s4, L1 add $s0, $s1, $s2 L1: sub $s0, $s0.$s3 请问最后$s0是多少

1. addi $s0, $zero,10：将寄存器$s0的值设置为10。 2. addi $s1, $zero, 3：将寄存器$s1的值设置为3。 3. addi $s2, $zero, 5：将寄存器$s2的值设置为5。 4. addi $s3, $zero,6：将寄存器$s3的值设置为6。 5. addi ...

addi $s0, $zero,10addi $s1, $zero, 3addi $s2, $zero, 5addi $s3, $zero,6addi $s4, $zero,6bne $s3, $s4, L1add $s0, $s1, $s2 L1: sub $s0, $s0.$s3

addi $s0, $zero, 10 2.将3赋值给寄存器$s1 addi $s1, $zero, 3 3.将5赋值给寄存器$s2 addi $s2, $zero, 5 4.将6赋值给寄存器$s3 addi $s3, $zero, 6 5.将6赋值给寄存器$s4 addi $...

.data array: .space 404 string: .asciiz "Input a number: \n" .text li $v0,4 la $a0,string syscall li $v0,5 syscall move $t2,$v0 move $t3,$t2 li $t0,1 la $t1,array sw $t0,($t1) sw $t0,4($t1) blt $t2,3,print Fib: addi $sp,$sp,-8 sw $ra,0($sp) sw $t2,4($sp) beq $t2,2,re addi $t2,$t2,-1 jal Fib move $t4,$0 lw $a0,($t1) lw $a1,4($t1) add $t4,$a1,$a0 sw $t4,8($t1) addi $t1,$t1,4 beq $t2,$t3,print re: lw $ra,0($sp) addi $t2,$t2,1 addi $sp,$sp,8 jr $ra print: la $t1,array li $t3,1 loop1: lw $a0,($t1) li $v0,1 syscall li $v0,11 li $a0,' ' syscall beq $t3,$t2,end addi $t3,$t3,1 addi $t1,$t1,4 b loop1 end: li $v0,10 syscall 写出该mips汇编语言的伪代码

13. 将$t1指针加4 14. 如果$t2等于$t3，则跳转到print标签处 15. 跳转到re标签处 16. 在print标签处，使用循环遍历数组array中的元素，并依次输出到屏幕上 17. 输出一个换行符 18. 结束程序

addi $s0, $zero, 10 addi $s1, $zero, 3 addi $s2, $zero, 5 addi $s3, $zero, 6 addi $s4, $zero, 7 beq $s3, $s4, L1 add $s0, $s1, $s2 L1: sub $s0, $s0, $s3

addi $s0, $zero, 10 2.将3存储到寄存器$s1中 addi $s1, $zero, 3 3.将5存储到寄存器$s2中 addi $s2, $zero, 5 4.将6存储到寄存器$s3中 addi $s3, $zero, 6 5.将7存储到寄存器$s4中 ...

addi $s0, $zero,10addi $s1, $zero,3addi $s2, $zero, 5addi $s3, $zero, 6addi $s4, $zero, 6bne $s3, $s4, L1add $s0, $s1,$s2 L1: sub $s0, $s0, $s3

它的作用是将 $s0 初始化为 10，$s1 初始化为 3，$s2 初始化为 5，$s3 初始化为 6，$s4 初始化为 6。然后它会比较 $s3 和 $s4 的值，如果它们不相等，就跳转到标记为 L1 的位置。在 L1 处，它将 $s0 设置为 $s1 + $...

翻译下列汇编.data prime: .space 14000 out_1: .asciiz " primes created. The last 10 primes is: \n" table: .asciiz "\n" nps: .asciiz " " tip1: .asciiz "Please input a number: \n" tip2: .asciiz "The next prime is: \n" tip3: .asciiz "The program is over! " tip4: .asciiz "The number out of range \n" .align 2 .globl main .text main: jal CreatePrimes jal NextPrime li $v0,10 syscall CreatePrimes: la $a1,prime li $t7,3 sw $t7,0($a1) addi $a1,$a1,2 li $t1,5 li $t2,1 li $t3,65536 loop: li $t4,3 loop2: divu $t1,$t4 mfhi $t0 beqz $t0,loop3 mul $t5,$t4,$t4 addi $t4,$t4,2 ble $t5,$t1,loop2 loop3: move $t7,$t4 mul $t8,$t7,$t7 ble $t8,$t1,else sh $t1,0($a1) addi $t2,$t2,1 addi $a1,$a1,2 else: addi $t1,$t1,2 blt $t1,65536,loop print: subi $t1,$t2,10 la $t3,prime mul $t7,$t1,2 add $t3,$t3,$t7 li $v0,1 move $a0,$t2 syscall li $v0,4 la $a0,out_1 syscall loop4: li $v0,1 lhu $a0,($t3) syscall li $v0,4 la $a0,nps syscall addi $t1,$t1,1 addi $t3,$t3,2 blt $t1,$t2,loop4 li $v0,4 la $a0,table syscall move $a0,$t2 jr $ra NextPrime: again: li $v0,4 la $a0,tip1 syscall li $v0,5 syscall beq $v0,2,out3 ble $v0,1,over bge $v0,65521,label move $t3,$v0 li $t1,0 la $t0,prime loop5: sll $t2, $t1, 1 add $t2, $t0, $t2 lhu $s0 0($t2) bge $s0,$t3,out2 addi $t1, $t1, 1 j loop5 out2: li $v0,4 la $a0,tip2 syscall li $v0,1 move $a0,$s0 syscall li $v0,4 la $a0,table syscall move $v0,$t1 j again out3: li $v0,4 la $a0,tip2 syscall li $v0,1 li $a0,2 syscall li $v0,4 la $a0,table syscall j again label: move $t1,$v0 li $t2,2 div $t1,$t2 mfhi $t4 bnez $t4,loop6 addi $t1,$t1,1 loop6: li $t4,3 loop7: div $t1,$t4 mfhi $t0 beqz $t0,loop8 mul $t5,$t4,$t4 move $t6,$t4 addi $t4,$t4,2 ble $t5,$t1,loop7 loop8: mul $t8,$t6,$t6 ble $t8,$t1,else1 j out else1: addi $t1,$t1,2 j loop6 out: li $v0,4 la $a0,tip2 syscall li $v0,1 move $a0,$t1 syscall li $v0,4 la $a0,table syscall move $v0 $t1 j again over: li $v0,4 la $a0,tip3 syscall jr $ra对这段代码进行优化

sw $zero,0($a1) # 2是第一个素数，所以直接存储 addi $a1,$a1,2 sw $at,0($a1) # 3是第二个素数，存储 addi $a1,$a1,2 li $t1,5 # 从5开始生成素数 li $t2,1 # 记录生成素数的个数 li $t3,65536 # 素数范围...

将下面的循环翻译成c代码。假定寄存器$t1中存放了c语言级的整数i，$s2中存放了c语言级的整数result，$s0存放正数组MemArray的基地址。 addi $t1, $0, 0 LOOP: lw $s1, 0($s0) add $s2, $s2, $s1 addi $s0, $s0, 4 addi $t1, $t1, 1 slti $t2, $t1, 100 bne $t2, $0, LOOP

int i = 0; int result = 0; int* MemArray; // 假设MemArray是一个整数数组的基地址 for (i = 0; i ; i++) { result += MemArray[i]; } 请注意，这只是一个基本的转换，并且假设变量和数组已经声明和初始化...

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用中文依次解释每一句的意思.text addi $t1,$zero,0 #init_addr addi $t3,$zero,32 #counter #sb写入 01,02,03,04 addi $s1,$zero, 0x00 # addi $s2,$zero, 0x01 # sb_store: sb $s1,-100($t1) add $a0,$0,$s1 addi $v0,$zero,34

在MIPS中，下面四个指令错误的是：A.add $t1,$t1,$t1 B.sub $t1,$t1,$t1 C.addi $t1,$t1,100 D.subi $t1,$t1,100

addi $s0, $zero,10 addi $s1, $zero, 3 addi $s2, $zero, 5 addi $s3, $zero,6 addi $s4, $zero,6 bne $s3, $s4, L1 add $s0, $s1, $s2 L1: sub $s0, $s0.$s3 请问最后$s0是多少

addi $s0, $zero,10addi $s1, $zero, 3addi $s2, $zero, 5addi $s3, $zero,6addi $s4, $zero,6bne $s3, $s4, L1add $s0, $s1, $s2 L1: sub $s0, $s0.$s3

addi $s0, $zero, 10 addi $s1, $zero, 3 addi $s2, $zero, 5 addi $s3, $zero, 6 addi $s4, $zero, 7 beq $s3, $s4, L1 add $s0, $s1, $s2 L1: sub $s0, $s0, $s3

addi $s0, $zero,10addi $s1, $zero,3addi $s2, $zero, 5addi $s3, $zero, 6addi $s4, $zero, 6bne $s3, $s4, L1add $s0, $s1,$s2 L1: sub $s0, $s0, $s3

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