在一段dlib眼部纵横比检测程序里,加入限定时间参数提取的代码python
时间: 2024-02-29 13:51:20 浏览: 102
好的,以下是一个简单的示例程序,用于检测眼部纵横比并在指定时间内返回结果:
```python
import dlib
import time
predictor_path = 'path/to/shape_predictor_68_face_landmarks.dat'
detector = dlib.get_frontal_face_detector()
predictor = dlib.shape_predictor(predictor_path)
def detect_eye_aspect_ratio(shape):
# 获取眼部坐标
left_eye = shape[42:48]
right_eye = shape[36:42]
# 计算纵横比
left_ear = eye_aspect_ratio(left_eye)
right_ear = eye_aspect_ratio(right_eye)
ear = (left_ear + right_ear) / 2.0
return ear
def eye_aspect_ratio(eye):
# 计算眼部纵横比
A = dist.euclidean(eye[1], eye[5])
B = dist.euclidean(eye[2], eye[4])
C = dist.euclidean(eye[0], eye[3])
ear = (A + B) / (2.0 * C)
return ear
def detect_eyes(image, timeout):
# 检测人脸
start_time = time.time()
faces = detector(image)
if not faces:
return None
# 获取人脸关键点
shape = predictor(image, faces[0])
# 计算眼部纵横比
ear = detect_eye_aspect_ratio(shape)
# 检测时间是否超时
while (time.time() - start_time) < timeout:
# 检测人脸
faces = detector(image)
if not faces:
return None
# 获取人脸关键点
shape = predictor(image, faces[0])
# 计算眼部纵横比
ear = detect_eye_aspect_ratio(shape)
return ear
```
在这个例子中,我们使用dlib库检测人脸并计算眼部纵横比。我们还添加了一个timeout参数来限制检测时间。程序将在超时时返回None,否则将返回计算出的眼部纵横比。请注意,这只是一个示例程序,您需要根据您的具体应用场景进行修改。
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