农历转阳历代码

以下是 Python 实现的农历转阳历代码：

import math

# 农历1900年到2049年每年的天数及每月的天数
lunar_month_days = [
    0x04bd8, 0x04ae0, 0x0a570, 0x054d5, 0x0d260, 0x0d950, 0x16554, 0x056a0,
    0x09ad0, 0x055d2, 0x04ae0, 0x0a5b6, 0x0a4d0, 0x0d250, 0x1d255, 0x0b540,
    0x0d6a0, 0x0ada2, 0x095b0, 0x14977, 0x04970, 0x0a4b0, 0x0b4b5, 0x06a50,
    0x06d40, 0x1ab54, 0x02b60, 0x09570, 0x052f2, 0x04970, 0x06566, 0x0d4a0,
    0x0ea50, 0x06e95, 0x05ad0, 0x02b60, 0x186e3, 0x092e0, 0x1c8d7, 0x0c950,
    0x0d4a0, 0x1d8a6, 0x0b550, 0x056a0, 0x1a5b4, 0x025d0, 0x092d0, 0x0d2b2,
    0x0a950, 0x0b557, 0x06ca0, 0x0b550, 0x15355, 0x04da0, 0x0a5d0, 0x14573,
    0x052d0, 0x0a9a8, 0x0e950, 0x06aa0, 0x0aea6, 0x0ab50, 0x04b60, 0x0aae4,
    0x0a570, 0x05260, 0x0f263, 0x0d950, 0x05b57, 0x056a0, 0x096d0, 0x04dd5,
    0x04ad0, 0x0a4d0, 0x0d4d4, 0x0d250, 0x0d558, 0x0b540, 0x0b5a0, 0x195a6,
    0x095b0, 0x049b0, 0x0a974, 0x0a4b0, 0x0b27a, 0x06a50, 0x06d40, 0x0af46,
    0x0ab60, 0x09570, 0x04af5, 0x04970, 0x064b0, 0x074a3, 0x0ea50, 0x06b58,
    0x055c0, 0x0ab60, 0x096d5, 0x092e0, 0x0c960, 0x0d954, 0x0d4a0, 0x0da50,
    0x07552, 0x056a0, 0x0abb7, 0x025d0, 0x092d0, 0x0cab5, 0x0a950, 0x0b4a0,
    0x0baa4, 0x0ad50, 0x055d9, 0x04ba0, 0x0a5b0, 0x15176, 0x052b0, 0x0a930,
    0x07954, 0x06aa0, 0x0ad50, 0x05b52, 0x04b60, 0x0a6e6, 0x0a4e0, 0x0d260,
    0x0ea65, 0x0d530, 0x05aa0, 0x076a3, 0x096d0, 0x04bd7, 0x04ad0, 0x0a4d0,
    0x1d0b6, 0x0d250, 0x0d520, 0x0dd45, 0x0b5a0, 0x056d0, 0x055b2, 0x049b0,
    0x0a577, 0x0a4b0, 0x0aa50, 0x1b255, 0x06d20, 0x0ada0
]

# 农历1900年的阳历日期
solar_1900 = (1900, 1, 31)

def is_leap(year):
    """判断是否为闰年"""
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

def lunar_to_solar(lunar_year, lunar_month, lunar_day):
    """农历转阳历"""
    # 计算农历日期与1900年1月31日相差的天数
    days_diff = 0
    for i in range(lunar_year - 1900):
        days_diff += 365 + int(is_leap(1900 + i))
    for i in range(lunar_month - 1):
        days_diff += (lunar_month_days[lunar_year - 1900] >> i) & 1
    days_diff += lunar_day - 1

    # 计算阳历日期
    solar_days = solar_1900[2] + days_diff
    solar_month = solar_1900[1]
    solar_year = solar_1900[0]
    while True:
        days_in_month = 28 + is_leap(solar_year) if solar_month == 2 else 31 - ((solar_month - 1) % 7 % 2)
        if solar_days > days_in_month:
            solar_days -= days_in_month
            solar_month += 1
            if solar_month > 12:
                solar_month = 1
                solar_year += 1
        else:
            break

    return solar_year, solar_month, solar_days

使用方法：

lunar_year = 2022
lunar_month = 1
lunar_day = 1
solar_year, solar_month, solar_day = lunar_to_solar(lunar_year, lunar_month, lunar_day)
print(f"农历{lunar_year}年{lunar_month}月{lunar_day}日对应的阳历日期为：{solar_year}年{solar_month}月{solar_day}日")

输出结果：

农历2022年1月1日对应的阳历日期为：2022年1月31日