请写出该C++程序
时间: 2024-02-27 17:58:24 浏览: 60
好的,以下是这个问题的C++程序实现:
```c++
#include<iostream>
using namespace std;
const int N = 100010;
int n;
int a[N], tmp[N];
void merge(int l, int r, int mid) {
int i = l, j = mid + 1, k = 0;
while (i <= mid && j <= r) {
if (a[i] <= a[j]) tmp[k ++] = a[i ++];
else tmp[k ++] = a[j ++];
}
while (i <= mid) tmp[k ++] = a[i ++];
while (j <= r) tmp[k ++] = a[j ++];
for (i = l, j = 0; i <= r; i ++, j ++) a[i] = tmp[j];
}
void mergeSort(int l, int r) {
if (l >= r) return;
int mid = (l + r) >> 1;
mergeSort(l, mid);
mergeSort(mid + 1, r);
merge(l, r, mid);
}
void print(int l, int r) {
for (int i = l; i <= r; i ++) {
cout << a[i] << ' ';
}
cout << '\n';
}
void dfs(int l, int r) {
if (l >= r) return;
int mid = (l + r) >> 1;
dfs(l, mid);
dfs(mid + 1, r);
print(l, r);
}
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) {
cin >> a[i];
}
mergeSort(1, n);
cout << n << '\n';
dfs(1, n);
return 0;
}
```
程序中使用了经典的归并排序算法,其中`merge`函数用于合并两个有序的子序列,`mergeSort`函数用于递归调用归并排序,`dfs`函数用于按照2路归并排序树的方式输出每个有序的子序列。
希望这个程序对您有所帮助!
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