file_path = 'E:\\PythonProjects\\tuxiangshibie\\485jixiebi\\baidu\\zuobiao'
时间: 2023-10-31 16:07:33 浏览: 22
这是一个文件路径,其中包含了文件夹名和文件名。具体来说,'E:\\PythonProjects\\tuxiangshibie\\485jixiebi\\baidu\\zuobiao' 表示该文件路径下有一个名为 'zuobiao' 的文件夹,该文件夹位于 'E:\\PythonProjects\\tuxiangshibie\\485jixiebi\\baidu' 这个路径下。如果你想访问该文件夹下的文件,可以使用相应的文件操作函数进行操作。
相关问题
将下面一段matlab代码转换为python代码(function point_bridge1 = zuobiao_qiao(global_coords,juli_qiaoche) %UNTITLED5 用于将桥梁绝对坐标转换为相对坐标 % 此处显示详细说明 local_coords(:,1) = global_coords(:,1) - global_coords(1,1); local_coords(:,2) = global_coords(:,2) - global_coords(1,2); % 计算1点和4点的连线向量 v = local_coords(2,:) - local_coords(1,:); % 计算旋转角度 theta = -atan2(v(2), v(1)); R = [cos(theta) -sin(theta); sin(theta) cos(theta)]; rotated_point = local_coords(:,:) * R; point_bridge1(:,1) = rotated_point (:,1) point_bridge1(1,2) = rotated_point(1,2)-juli_qiaoche(1); point_bridge1(2,2) = rotated_point(2,2)+juli_qiaoche(2); point_bridge1(3,2) = rotated_point(3,2)+juli_qiaoche(3); point_bridge1(4,2) = rotated_point(4,2)-juli_qiaoche(4); point_bridge1(:,2) = point_bridge1(:,2) - point_bridge1(1,2); end)
以下是将 MATLAB 代码转换为 Python 代码后的结果:
```python
import numpy as np
def zuobiao_qiao(global_coords, juli_qiaoche):
local_coords = np.zeros_like(global_coords)
local_coords[:, 0] = global_coords[:, 0] - global_coords[0, 0]
local_coords[:, 1] = global_coords[:, 1] - global_coords[0, 1]
v = local_coords[1, :] - local_coords[0, :]
theta = -np.arctan2(v[1], v[0])
R = np.array([[np.cos(theta), -np.sin(theta)], [np.sin(theta), np.cos(theta)]])
rotated_point = np.dot(local_coords, R)
point_bridge1 = np.zeros((4, 2))
point_bridge1[:, 0] = rotated_point[:, 0]
point_bridge1[0, 1] = rotated_point[0, 1] - juli_qiaoche[0]
point_bridge1[1, 1] = rotated_point[1, 1] + juli_qiaoche[1]
point_bridge1[2, 1] = rotated_point[2, 1] + juli_qiaoche[2]
point_bridge1[3, 1] = rotated_point[3, 1] - juli_qiaoche[3]
point_bridge1[:, 1] = point_bridge1[:, 1] - point_bridge1[0, 1]
return point_bridge1
```
请注意,这里使用的是 NumPy 库中的矩阵运算,因此需要将输入的数组转换为 NumPy 数组。此外,由于 Python 中的索引从 0 开始,因此在 Python 代码中需要将索引减去 1。
把以下matlab代码转换为python代码(clear;clc; global_coords = [10, 10; 20, 20; 40, 20; 30, 10];%%%%测量时候桥梁坐标 juli_qiaoche =[2,2,2,2];%%%%测量时候车辆中心距离距离桥梁距离 % 转换为局部坐标 point_bridge1 = zuobiao_qiao( global_coords,juli_qiaoche ))
以下是将 MATLAB 代码转换为 Python 代码后的结果:
```python
import numpy as np
def zuobiao_qiao(global_coords, juli_qiaoche):
local_coords = np.zeros_like(global_coords)
local_coords[:, 0] = global_coords[:, 0] - global_coords[0, 0]
local_coords[:, 1] = global_coords[:, 1] - global_coords[0, 1]
v = local_coords[1, :] - local_coords[0, :]
theta = -np.arctan2(v[1], v[0])
R = np.array([[np.cos(theta), -np.sin(theta)], [np.sin(theta), np.cos(theta)]])
rotated_point = np.dot(local_coords, R)
point_bridge1 = np.zeros((4, 2))
point_bridge1[:, 0] = rotated_point[:, 0]
point_bridge1[0, 1] = rotated_point[0, 1] - juli_qiaoche[0]
point_bridge1[1, 1] = rotated_point[1, 1] + juli_qiaoche[1]
point_bridge1[2, 1] = rotated_point[2, 1] + juli_qiaoche[2]
point_bridge1[3, 1] = rotated_point[3, 1] - juli_qiaoche[3]
point_bridge1[:, 1] = point_bridge1[:, 1] - point_bridge1[0, 1]
return point_bridge1
global_coords = np.array([[10, 10], [20, 20], [40, 20], [30, 10]])
juli_qiaoche = np.array([2, 2, 2, 2])
point_bridge1 = zuobiao_qiao(global_coords, juli_qiaoche)
print(point_bridge1)
```
请注意,在 Python 中,您需要从 NumPy 库中导入 `numpy`,并且在调用函数时需要将输入的数组转换为 NumPy 数组。此外,Matlab 中的 `clear` 和 `clc` 不需要在 Python 中使用。最后,您可以使用 `print(point_bridge1)` 打印输出 `point_bridge1`。
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