pareto最优解 python程序
时间: 2024-05-16 07:18:27 浏览: 197
以下是一些可能的解法,但并不一定是 Pareto 最优解的实现:
1. 使用 scipy.optimize 中的 minimize 方法实现 Pareto 最优解:
```python
from scipy.optimize import minimize
def f1(x):
return -x[0]
def f2(x):
return -x[1]
def constraint1(x):
return x[0] + x[1] - 1.5
cons = ({'type': 'ineq', 'fun': constraint1})
x0 = [0, 0]
res = minimize([f1, f2], x0, constraints=cons, method='COBYLA')
print(res.x)
```
2. 使用 DEAP 库实现 Pareto 最优解:
```python
import random
from deap import algorithms, base, creator, tools
creator.create("Fitness", base.Fitness, weights=(-1.0, -1.0))
creator.create("Individual", list, fitness=creator.Fitness)
toolbox = base.Toolbox()
toolbox.register("attr_float", random.uniform, 0, 1.5)
toolbox.register("individual", tools.initRepeat, creator.Individual, toolbox.attr_float, 2)
toolbox.register("population", tools.initRepeat, list, toolbox.individual)
def evaluate(individual):
return -individual[0], -individual[1]
toolbox.register("evaluate", evaluate)
toolbox.register("mate", tools.cxTwoPoint)
toolbox.register("mutate", tools.mutGaussian, mu=0, sigma=0.5, indpb=0.1)
toolbox.register("select", tools.selNSGA2)
pop = toolbox.population(n=50)
hof = tools.ParetoFront()
stats = tools.Statistics(lambda ind: ind.fitness.values)
stats.register("avg", tools.mean, axis=0)
stats.register("std", tools.std, axis=0)
stats.register("min", tools.min, axis=0)
stats.register("max", tools.max, axis=0)
pop, logbook = algorithms.eaSimple(pop, toolbox, cxpb=0.5, mutpb=0.2, ngen=100, halloffame=hof, stats=stats)
print(hof[0])
```
这是两种可能的 Pareto 最优解实现方法,但并不一定是最优解,具体实现还需根据具体问题的特点进行调整。
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