输入任意字符,用16进制形式显示他的ASCII码值,汇编语言,简洁一些
时间: 2024-02-28 11:29:24 浏览: 158
答案:
```
MOV AH, 02h ; 设置 AH 为输出字符指令
MOV DL, [input_char] ; 将输入字符存入 DL 中
INT 21h ; 输出字符
MOV AH, 02h ; 设置 AH 为输出字符指令
MOV DL, 0Dh ; 换行符
INT 21h ; 输出字符
MOV AH, 02h ; 设置 AH 为输出字符指令
MOV DL, 0Ah ; 换行符
INT 21h ; 输出字符
MOV AH, 02h ; 设置 AH 为输出字符指令
MOV DL, 0 ; 将 DL 清零,准备存放 ASCII 码值
MOV AL, [input_char] ; 将输入字符存入 AL 中
INT 21h ; 输出字符的 ASCII 码值
HLT ; 程序结束
input_char DB " " ; 定义输入字符变量
```
注:上面代码中的 `input_char` 变量可以通过键盘输入获得。
相关问题
汇编语言编程实现由键盘输入任意一个字符,将该字符用十六进制形式显示出它的 ASCII 码值
好的,我可以为您提供汇编语言的代码来实现该功能。请查看以下代码:
```assembly
section .data
msg db 'Enter a character: ' ; prompt message
hex db 'The ASCII code in hex is: 0x' ; message for hex value
section .bss
char resb 1 ; allocate one byte of memory for input character
section .text
global _start
_start:
; print prompt message
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor for stdout
mov ecx, msg ; address of message to write
mov edx, 17 ; number of bytes to write
int 0x80 ; call kernel
; read one character from keyboard
mov eax, 3 ; system call for read
mov ebx, 0 ; file descriptor for stdin
mov ecx, char ; address to store input character
mov edx, 1 ; number of bytes to read
int 0x80 ; call kernel
; convert input character to hexadecimal
mov eax, 0 ; clear eax register
mov al, [char] ; move input character to al register
mov ebx, 16 ; move the base of hexadecimal to ebx
xor edx, edx ; clear edx register
div ebx ; divide al by ebx (16)
add al, 0x30 ; convert remainder (0-9) to ASCII code
cmp al, 0x3A ; check remainder (0-9)
jna .hex ; jump to hex routine if remainder is less than 10
add al, 7 ; convert remainder (A-F) to ASCII code
.hex:
push eax ; push remainder to stack
mov eax, 4 ; call write system call
mov ebx, 1 ; write to stdout
mov ecx, hex ; message for hex value
mov edx, 27 ; number of bytes to write
int 0x80 ; call kernel
pop eax ; pop remainder from stack
add al, 0x30 ; convert quotient (0-9) to ASCII code
cmp al, 0x3A ; check quotient (0-9)
jna .next ; jump to next character if quotient is less than 10
add al, 7 ; convert quotient (A-F) to ASCII code
.next:
mov ebx, 16 ; move the base of hexadecimal to ebx
xor edx, edx ; clear edx register
div ebx ; divide the quotient by ebx (16)
push ax ; push remainder to stack
cmp al, 0 ; check quotient
jz .print ; jump to print routine if quotient is 0
add al, 0x30 ; convert quotient (0-9) to ASCII code
cmp al, 0x3A ; check quotient (0-9)
jna .next ; jump to next character if quotient is less than 10
add al, 7 ; convert quotient (A-F) to ASCII code
jmp .next ; repeat until quotient is 0
.print:
pop eax ; pop remainder (least significant bit) from stack
add al, 0x30 ; convert remainder to ASCII code
cmp al, 0x3A ; check remainder (0-9)
jna .last ; jump to last character if remainder is less than 10
add al, 7 ; convert remainder (A-F) to ASCII code
.last:
mov ebx, 1 ; write to stdout
mov ecx, eax ; result in al register
mov edx, 1 ; number of bytes to write
mov eax, 4 ; call write system call
int 0x80 ; call kernel
; exit gracefully
mov eax, 1 ; system call for exit
xor ebx, ebx ; exit with code 0
int 0x80 ; call kernel
```
您只需将上述代码保存为.asm文件,然后使用汇编器和链接器将其转换为可执行文件即可。请注意,此代码是针对x86架构编写的,如果您的计算机使用其他架构,则需要相应地更改代码。
汇编语言:从键盘输入一个字符,在下一行上以16进制形式输出它的ASCII码。
可以的,以下是汇编语言代码:
```
section .data
prompt db "Please enter a character: "
newline db 0Ah
section .bss
input resb 1
section .text
global _start
_start:
; print prompt message
mov eax, 4
mov ebx, 1
mov ecx, prompt
mov edx, 23
int 80h
; read input
mov eax, 3
mov ebx, 0
mov ecx, input
mov edx, 1
int 80h
; print newline character
mov eax, 4
mov ebx, 1
mov ecx, newline
mov edx, 1
int 80h
; convert input to hex and print
mov eax, input
mov ebx, 0
mov ecx, 16
mov edx, 2
call bin2hex
; exit program
mov eax, 1
xor ebx, ebx
int 80h
bin2hex:
; converts binary value in eax to two-digit hex value and stores it in ecx
mov ebx, eax
shr ebx, 4
call byte2hex
mov [ecx], al
mov ebx, eax
and ebx, 0Fh
call byte2hex
mov [ecx+1], al
ret
byte2hex:
; converts binary value in bl to hex character and stores it in al
cmp bl, 9
jbe .digit
add bl, 7
.digit:
add bl, 30h
mov al, bl
ret
```
运行后,程序会提示用户输入一个字符,然后以16进制形式输出它的ASCII码。
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