用C语言写五子棋游戏能用vs运行的

以下为C语言实现五子棋游戏的示例代码：

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>

#define ROW 15
#define COL 15

void gotoxy(int x, int y) {
    COORD c;
    c.X = x;
    c.Y = y;
    SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), c);
}

void draw_board() {
    int i, j;
    printf("\n\n");
    for (i = 0; i < ROW; i++) {
        gotoxy(20, i + 2);
        for (j = 0; j < COL; j++) {
            if (i == 0 && j == 0)
                printf("┌");
            else if (i == 0 && j == COL - 1)
                printf("┐");
            else if (i == ROW - 1 && j == 0)
                printf("└");
            else if (i == ROW - 1 && j == COL - 1)
                printf("┘");
            else if (i == 0 || i == ROW - 1)
                printf("─");
            else if (j == 0 || j == COL - 1)
                printf("│");
            else
                printf("┼");
        }
    }
}

void print_piece(int x, int y, int player) {
    gotoxy(y * 2 + 20, x + 2);
    if (player == 1)
        printf("●");
    else
        printf("○");
}

int check_win(int board[][COL], int x, int y, int player) {
    int i, j;
    int count = 0;

    // check row
    for (i = y - 4; i <= y; i++) {
        if (i < 0 || i + 4 >= COL)
            continue;
        count = 0;
        for (j = i; j <= i + 4; j++) {
            if (board[x][j] == player)
                count++;
            else
                break;
        }
        if (count == 5)
            return 1;
    }

    // check column
    for (i = x - 4; i <= x; i++) {
        if (i < 0 || i + 4 >= ROW)
            continue;
        count = 0;
        for (j = i; j <= i + 4; j++) {
            if (board[j][y] == player)
                count++;
            else
                break;
        }
        if (count == 5)
            return 1;
    }

    // check diagonal
    for (i = x - 4; i <= x; i++) {
        if (i < 0 || i + 4 >= ROW)
            continue;
        count = 0;
        for (j = 0; j < 5; j++) {
            if (board[i+j][y+i-j] == player)
                count++;
            else
                break;
        }
        if (count == 5)
            return 1;
    }

    // check anti-diagonal
    for (i = x - 4; i <= x; i++) {
        if (i < 0 || i + 4 >= ROW || y + 4 >= COL)
            continue;
        count = 0;
        for (j = 0; j < 5; j++) {
            if (board[i+j][y-j] == player)
                count++;
            else
                break;
        }
        if (count == 5)
            return 1;
    }

    return 0;
}

int main() {
    int board[ROW][COL] = {0};
    int player = 1;
    int x, y;

    draw_board();

    while (1) {
        printf("\nPlayer %d's turn: ", player);
        scanf("%d%d", &x, &y);

        if (x < 1 || x > 15 || y < 1 || y > 15) {
            printf("Invalid input! Please enter again.\n");
            continue;
        }

        if (board[x-1][y-1] != 0) {
            printf("The position has been taken! Please choose another one.\n");
            continue;
        }

        board[x-1][y-1] = player;
        print_piece(x-1, y-1, player);

        if (check_win(board, x-1, y-1, player)) {
            printf("\nPlayer %d wins!\n", player);
            break;
        }

        player = player == 1 ? 2 : 1;
    }

    return 0;
}

该程序使用了头文件 `<windows.h>` 和函数 `SetConsoleCursorPosition()` 来实现光标移动和清屏功能，因此需要在 Windows 系统下编译和运行。在 Visual Studio 中，可以使用以下步骤运行该程序：

1. 创建一个新的控制台应用程序项目。
2. 将上述代码复制到“main.c”文件中。
3. 在菜单栏中选择“生成”->“生成解决方案”来编译程序。
4. 点击“本地 Windows 调试器”按钮或按下“F5”键来运行程序。

运行程序后，程序将在控制台中显示出一个五子棋棋盘，玩家可以通过输入坐标来下棋，并且程序会判断是否有玩家获胜。