如何用python的scrapy框架爬取js翻页
时间: 2024-06-10 07:06:38 浏览: 162
python基于scrapy爬取网页信息
可以使用Scrapy中的Selenium中间件来处理JavaScript渲染的网页,从而实现翻页。具体实现可以参考以下步骤:
1. 安装Selenium:可以使用pip或conda来安装,建议使用conda安装。
```
conda install -c conda-forge selenium
```
2. 在Scrapy的settings.py中启用Selenium中间件:
```
DOWNLOADER_MIDDLEWARES = {
'scrapy_selenium.SeleniumMiddleware': 800
}
```
3. 使用Selenium来获取待抓取页面的真实链接,并传递给Scrapy的下载器进行下载和解析。例如,以下代码使用Selenium中的WebDriver来获取每个JS渲染的页面的真实链接,并将其传递给Scrapy的下载器。
```python
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import Rule, CrawlSpider
from scrapy.selector import Selector
from scrapy_selenium import SeleniumRequest
class MySpider(CrawlSpider):
name = 'example.com'
allowed_domains = ['example.com']
start_urls = ['http://www.example.com/']
rules = (
Rule(LinkExtractor(), callback='parse_page', follow=True),
)
def start_requests(self):
for url in self.start_urls:
yield SeleniumRequest(url=url, callback=self.parse, wait_time=10)
def parse_page(self, response):
sel = Selector(text=response.body)
# do something with selectors
pass
```
4. 在Scrapy中实现翻页功能。例如,以下代码展示如何实现翻页:
```python
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import Rule, CrawlSpider
from scrapy.selector import Selector
from scrapy_selenium import SeleniumRequest
class MySpider(CrawlSpider):
name = 'example.com'
allowed_domains = ['example.com']
start_urls = ['http://www.example.com/']
rules = (
Rule(LinkExtractor(), callback='parse_page', follow=True),
)
def start_requests(self):
for url in self.start_urls:
yield SeleniumRequest(url=url, callback=self.parse, wait_time=10)
def parse_page(self, response):
sel = Selector(text=response.body)
# do something with selectors
# 翻页操作
if sel.xpath('//a[@class="next"]/@href'): # 判断是否有下一页
next_page = sel.xpath('//a[@class="next"]/@href')[0]
yield SeleniumRequest(url=response.urljoin(next_page), callback=self.parse_page, wait_time=10)
```
其中,需要根据实际网站的翻页方式进行相应的修改。
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