假设员工的姓均为姓名中的第1个字符。编写程序，统计下列列表中各姓氏所含的人数。 测试示例如下： 列表如下： incomeList = [ ['10932','张珊',15000.00 ,4000.00 ,2300.00 ,980.00 ,300.00 ,1000.00], ['10933','李思',12000.00 ,5000.00 ,2600.00 ,890.00 ,400.00 ,2000.00], ['10934','王武',10100.00 ,2000.00 ,2500.00 ,860.00 ,500.00 ,1500.00], ['10935','赵柳',10050.00 ,1000.00 ,2700.00 ,1080.00 ,300.00 ,2000.00], ['10936','钱棋',10200.00 ,2000.00 ,2400.00 ,1000.00 ,600.00 ,1000.00], ['10941','张明',13600.00 ,4000.00 ,2100.00 ,680.00 ,300.00 ,1000.00], ['10942','赵敏',13200.00 ,2500.00 ,2300.00 ,670.00 ,400.00 ,3000.00], ['10945','王红',13600.00 ,2600.00 ,2030.00 ,560.00 ,400.00 ,2000.00], ['10946','李萧',12500.00 ,2800.00 ,2400.00 ,420.00 ,500.00 ,1500.00], ['10947','孙科',12000.00 ,3500.00 ,2030.00 ,880.00 ,300.00 ,1000.00], ['10948','刘利',14200.00 ,2500.00 ,2020.00 ,900.00 ,400.00 ,2000.00] ]

你可以使用 Python 的字典 (dictionary) 来实现这个统计。具体思路是，遍历列表中每个员工的姓名，取出姓氏第一个字符，然后检查字典中是否已经有这个姓氏。如果有，将对应的计数器加1；如果没有，将这个姓氏作为键，计数器初始化为1，加入字典中。

下面是实现代码：

incomeList = [
    ['10932','张珊',15000.00 ,4000.00 ,2300.00 ,980.00 ,300.00 ,1000.00],
    ['10933','李思',12000.00 ,5000.00 ,2600.00 ,890.00 ,400.00 ,2000.00],
    ['10934','王武',10100.00 ,2000.00 ,2500.00 ,860.00 ,500.00 ,1500.00],
    ['10935','赵柳',10050.00 ,1000.00 ,2700.00 ,1080.00 ,300.00 ,2000.00],
    ['10936','钱棋',10200.00 ,2000.00 ,2400.00 ,1000.00 ,600.00 ,1000.00],
    ['10941','张明',13600.00 ,4000.00 ,2100.00 ,680.00 ,300.00 ,1000.00],
    ['10942','赵敏',13200.00 ,2500.00 ,2300.00 ,670.00 ,400.00 ,3000.00],
    ['10945','王红',13600.00 ,2600.00 ,2030.00 ,560.00 ,400.00 ,2000.00],
    ['10946','李萧',12500.00 ,2800.00 ,2400.00 ,420.00 ,500.00 ,1500.00],
    ['10947','孙科',12000.00 ,3500.00 ,2030.00 ,880.00 ,300.00 ,1000.00],
    ['10948','刘利',14200.00 ,2500.00 ,2020.00 ,900.00 ,400.00 ,2000.00]
]

count_dict = {}

for employee in incomeList:
    first_char = employee[1][0]
    if first_char in count_dict:
        count_dict[first_char] += 1
    else:
        count_dict[first_char] = 1

print(count_dict)

输出结果为：

{'张': 2, '李': 2, '王': 2, '赵': 2, '钱': 1, '孙': 1, '刘': 1}

这说明，姓张、李、王、赵各有2人，姓钱、孙、刘各有1人。