给定一个年份输出对应生肖c语言代码

### 回答1：
以下是给定一个年份输出对应生肖的 C 语言代码：

#include <stdio.h>

int main() {
int year;
printf("请输入年份：");
scanf("%d", &year);

switch (year % 12) {
case :
printf("%d年是猴年\n", year);
break;
case 1:
printf("%d年是鸡年\n", year);
break;
case 2:
printf("%d年是狗年\n", year);
break;
case 3:
printf("%d年是猪年\n", year);
break;
case 4:
printf("%d年是鼠年\n", year);
break;
case 5:
printf("%d年是牛年\n", year);
break;
case 6:
printf("%d年是虎年\n", year);
break;
case 7:
printf("%d年是兔年\n", year);
break;
case 8:
printf("%d年是龙年\n", year);
break;
case 9:
printf("%d年是蛇年\n", year);
break;
case 10:
printf("%d年是马年\n", year);
break;
case 11:
printf("%d年是羊年\n", year);
break;
}

return ;
}

### 回答2：
#include <stdio.h>

int main() {
int year;
printf("请输入年份：");
scanf("%d", &year);

int zodiac = (year - 1900) % 12;

switch(zodiac) {
case 0:
printf("鼠");
break;
case 1:
printf("牛");
break;
case 2:
printf("虎");
break;
case 3:
printf("兔");
break;
case 4:
printf("龙");
break;
case 5:
printf("蛇");
break;
case 6:
printf("马");
break;
case 7:
printf("羊");
break;
case 8:
printf("猴");
break;
case 9:
printf("鸡");
break;
case 10:
printf("狗");
break;
case 11:
printf("猪");
break;
default:
printf("请重新输入有效年份。");
break;
}

return 0;
}

### 回答3：
下面是一个用C语言实现的根据年份输出对应生肖的代码：

#include <stdio.h>

int main() {
    int year;
    printf("请输入一个年份：");
    scanf("%d", &year);
    
    switch (year % 12) {
        case 0:
            printf("%d年是猴年\n", year);
            break;
        case 1:
            printf("%d年是鸡年\n", year);
            break;
        case 2:
            printf("%d年是狗年\n", year);
            break;
        case 3:
            printf("%d年是猪年\n", year);
            break;
        case 4:
            printf("%d年是鼠年\n", year);
            break;
        case 5:
            printf("%d年是牛年\n", year);
            break;
        case 6:
            printf("%d年是虎年\n", year);
            break;
        case 7:
            printf("%d年是兔年\n", year);
            break;
        case 8:
            printf("%d年是龙年\n", year);
            break;
        case 9:
            printf("%d年是蛇年\n", year);
            break;
        case 10:
            printf("%d年是马年\n", year);
            break;
        case 11:
            printf("%d年是羊年\n", year);
            break;
        default:
            printf("输入年份有误\n");
            break;
    }
    
    return 0;
}

这段代码首先提示用户输入一个年份，然后通过对年份取模12的结果来判断生肖。根据所得的结果在switch语句中输出对应的生肖。如果输入的年份不在范围内，代码会输出提示信息。