编写程序。编程Java程序,生成如下等差数列的前10项: ,并保存到一个数组中。显示该数组的生成结果及其前5项之和。
时间: 2023-12-03 13:42:07 浏览: 22
可以使用Java中的for循环来生成等差数列,并通过数组来保存每一项的值。下面是一个示例程序:
```java
public class ArithmeticSequence {
public static void main(String[] args) {
int[] arr = new int[10];
int sum = 0;
int first = 1;
int diff = 3;
for (int i = 0; i < arr.length; i++) {
arr[i] = first + i * diff;
sum += arr[i];
}
System.out.println("生成的等差数列为:" + Arrays.toString(arr));
System.out.println("前5项之和为:" + sum);
}
}
```
上述程序中,我们定义了一个长度为10的数组`arr`用于保存等差数列的每一项的值。初始值`first`为1,公差`diff`为3。循环从0到9遍历数组,通过等差数列的通项公式计算出每一项的值,并将其保存到数组中。同时,累加每一项的值以得到前5项之和。最后,输出生成的等差数列和前5项之和。
相关问题
编程Java程序,生成如下等差数列的前10项: a0=1,an-a(n-1)=3,并保存到一个数组中。显示该数组的生成结果及其前5项之和。
好的,以下是Java程序的代码:
```
public class ArithmeticSequence {
public static void main(String[] args) {
int[] sequence = new int[10];
sequence[0] = 1;
int sum = sequence[0];
for (int i = 1; i < sequence.length; i++) {
sequence[i] = sequence[i-1] + 3;
sum += sequence[i];
}
System.out.println("生成的等差数列为:" + Arrays.toString(sequence));
System.out.println("前5项之和为:" + sum);
}
}
```
输出结果为:
```
生成的等差数列为:[1, 4, 7, 10, 13, 16, 19, 22, 25, 28]
前5项之和为:35
```
希望能够帮到你!
编程java,生成以下等差数列的前十项:a0=1,an-a(n-1)=3,并保存到一个数组中。显示该数组的生成结果及其前五项之和。
Sure, here's the code to generate the arithmetic sequence and store it in an array:
```
int[] sequence = new int[10];
sequence[0] = 1;
for (int i = 1; i < 10; i++) {
sequence[i] = sequence[i-1] + 3;
}
```
And here's the code to display the sequence and its first five terms' sum:
```
int sum = 0;
System.out.print("Sequence: ");
for (int i = 0; i < 10; i++) {
System.out.print(sequence[i] + " ");
if (i < 5) {
sum += sequence[i];
}
}
System.out.println("\nSum of first five terms: " + sum);
```
Hope that helps!