使用c++，基于顺序栈实现十进制数到八进制数的转换

#include <stdio.h>
#include <stdlib.h>

#define STACK_SIZE 100

typedef struct {
    int* data;
    int top;
} Stack;

Stack* initStack() {
    Stack* s = (Stack*)malloc(sizeof(Stack));
    s->data = (int*)malloc(sizeof(int) * STACK_SIZE);
    s->top = -1;
    return s;
}

void push(Stack* s, int x) {
    s->data[++s->top] = x;
}

int pop(Stack* s) {
    return s->data[s->top--];
}

int isEmpty(Stack* s) {
    return s->top == -1;
}

void convert(int n) {
    Stack* s = initStack();
    while (n) {
        push(s, n % 8);
        n /= 8;
    }
    while (!isEmpty(s)) {
        printf("%d", pop(s));
    }
    printf("\n");
}

int main() {
    int n;
    printf("Please input a decimal number: ");
    scanf("%d", &n);
    printf("The octal number is: ");
    convert(n);
    return 0;
}