桌子上有一只盘子,每次只能放一只水果。爸爸专向盘子中放苹果,妈妈专向盘子中放橘子,一个儿子专等吃盘子中的橘子,一个女儿专等吃盘子中的苹果。用PV操作实现他们之间的同步机制。
时间: 2024-12-25 20:28:43 浏览: 10
这是一个典型的生产者-消费者问题,可以用互斥锁(Mutex)和条件变量(ConditionVariable)来解决。在Python中,可以使用`threading`模块来实现这个场景:
```python
import threading
class FruitBasket:
def __init__(self):
self.apple = 'Apple'
self.orange = 'Orange'
self.lock = threading.Lock()
self.condition = threading.Condition(self.lock)
self.eaten = False
def put_fruit(self, fruit_type, who):
with self.lock:
if fruit_type == self.apple:
print(f"{who} is putting an apple.")
self.eaten = False
self.condition.notify_all() # Notify all waiting consumers
elif fruit_type == self.orange:
print(f"{who} is putting an orange.")
self.eaten = False
self.condition.notify_all()
# If the basket is full (for simplicity, assume only one type of fruit at a time)
if self.eaten:
self.condition.wait() # Wait until someone eats the current fruit
def eat_fruit(self):
with self.lock:
while True:
if not self.eaten:
print(f"Someone eats ({self.apple} if available) and the basket becomes empty.")
self.eaten = True
break
else:
self.condition.wait() # Wait until there's a fruit to eat
# Consumers
dad = threading.Thread(target=FruitBasket().eat_fruit, name="Dad")
mom = threading.Thread(target=FruitBasket().eat_fruit, name="Mom")
# Producers
son = threading.Thread(target=FruitBasket().put_fruit, args=("Orange", "Son"), name="Son")
daughter = threading.Thread(target=FruitBasket().put_fruit, args=("Apple", "Daughter"), name="Daughter")
dad.start()
mom.start()
son.start()
daughter.start()
dad.join()
mom.join()
son.join()
daughter.join()
```
在这个例子中,每个线程分别代表爸爸、妈妈和孩子,他们会通过`put_fruit`和`eat_fruit`方法相互协作。生产者在`put_fruit`函数中放置水果并唤醒等待的消费者,而消费者在`eat_fruit`函数中检查是否有水果,并在有水果时吃掉。通过互斥锁保证同一时间只有一个操作在进行,而条件变量则用于控制何时通知其他线程。
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