使用turtle库、time库编程实现自己的七段数码管式学号202205404029

好的，我知道了。以下是实现代码：

import turtle
import time

# 定义数字的七段式编码
segments = [
    (0, 1, 2, 4, 5, 6),  # 0
    (2, 5),  # 1
    (0, 2, 3, 4, 6),  # 2
    (0, 2, 3, 5, 6),  # 3
    (1, 2, 3, 5),  # 4
    (0, 1, 3, 5, 6),  # 5
    (0, 1, 3, 4, 5, 6),  # 6
    (0, 2, 5),  # 7
    (0, 1, 2, 3, 4, 5, 6),  # 8
    (0, 1, 2, 3, 5, 6)  # 9
]

# 定义画笔位置及画笔大小
pos = [(0, 50), (80, 50), (80, 0), (0, -50), (80, -50), (0, -100), (80, -100)]
size = 40

# 定义画七段数码管的函数
def draw_segment(num, turtle):
    for i in segments[num]:
        if i == 0:
            turtle.penup()
            turtle.goto(pos[0])
            turtle.pendown()
            turtle.setheading(0)
            turtle.forward(size)
        if i == 1:
            turtle.penup()
            turtle.goto(pos[1])
            turtle.pendown()
            turtle.setheading(90)
            turtle.forward(size)
        if i == 2:
            turtle.penup()
            turtle.goto(pos[2])
            turtle.pendown()
            turtle.setheading(90)
            turtle.forward(size)
        if i == 3:
            turtle.penup()
            turtle.goto(pos[3])
            turtle.pendown()
            turtle.setheading(0)
            turtle.forward(size)
        if i == 4:
            turtle.penup()
            turtle.goto(pos[4])
            turtle.pendown()
            turtle.setheading(0)
            turtle.forward(size)
        if i == 5:
            turtle.penup()
            turtle.goto(pos[5])
            turtle.pendown()
            turtle.setheading(90)
            turtle.forward(size)
        if i == 6:
            turtle.penup()
            turtle.goto(pos[6])
            turtle.pendown()
            turtle.setheading(90)
            turtle.forward(size)

# 初始化画布和画笔
turtle.setup(400, 200)
turtle.penup()
turtle.hideturtle()

# 循环绘制数字
for num in '202205404029':
    draw_segment(int(num), turtle)
    time.sleep(0.5)

# 等待用户关闭窗口
turtle.done()

运行这段代码后，就会在屏幕上绘制出类似于七段数码管的形式显示出你的学号：202205404029。