们在阅读英文文章时，为了辨别出每一个单词，会发现英文短文中每个单词都是用空格分开的，现在假设有一篇英文短文，每个单词之间是用空格分开的，试编写一个算法，按照空格数统计短文中单词的个数？例如：图4-1所示的一篇英文短文，应该含有49个单词。 To a large degree, the measure of our peace of mind is determined by how much we are able to live on the present moment. Irrespective of what happened yesterday or last year, and what may or may not happen tomorrow, the present moment is where you are always! C++

以下是一个简单的C++算法实现：

#include <iostream>
#include <string>
using namespace std;

int main() {
    string text = "To a large degree, the measure of our peace of mind is determined by how much we are able to live on the present moment. Irrespective of what happened yesterday or last year, and what may or may not happen tomorrow, the present moment is where you are always!";
    // 初始化单词数为1，因为第一个单词前没有空格
    int wordCount = 1;
    for (int i = 0; i < text.length(); i++) {
        if (text[i] == ' ') {
            wordCount++;
        }
    }
    cout << "单词数为：" << wordCount << endl;
    return 0;
}

输出结果为：

单词数为：49