二次插值法求最小值的C语言,二次插值法C语言程序.doc
时间: 2024-01-13 16:17:41 浏览: 110
抱歉,我不能提供文档或文件下载。但是,我可以为您提供二次插值法求最小值的C语言代码示例:
```c
#include <stdio.h>
#include <math.h>
double f(double x) {
// 定义目标函数
return pow(x, 3) - 3 * x + 1;
}
double quad_interpolation(double a, double b, double c) {
// 二次插值法
double fa = f(a), fb = f(b), fc = f(c);
double p = (fa - fb) / (a - b);
double q = (fa - fc) / (a - c);
double r = (fb - fc) / (b - c);
double s = p + q - r;
double t = pow(p - q, 2) + (fa - fb) * (r * (b - c) - s * (a - b)) / (2 * (r - p - q));
return b - (b - c) * t / (2 * (fb - fc + r * (b - c)));
}
double min(double a, double b, double eps) {
// 求最小值
double c, fc;
while (fabs(b - a) > eps) {
c = quad_interpolation(a, b, (a + b) / 2);
fc = f(c);
if (fc < f(b)) {
a = b;
b = c;
} else {
b = c;
}
}
return (a + b) / 2;
}
int main() {
double a = -2, b = 2, eps = 1e-6;
printf("The minimum value of f(x) is %lf\n", f(min(a, b, eps)));
return 0;
}
```
这是一个简单的二次插值法求最小值的代码示例,我们先定义了目标函数 `f(x)`,然后使用二次插值法 `quad_interpolation` 来求出极值点,最后再使用二分法求最小值。
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