c语言 用3种循环分别计算1+2+3+…+100的结果
时间: 2023-09-20 11:11:12 浏览: 52
1. for循环
```c
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 1; i <= 100; i++) {
sum += i;
}
printf("1 + 2 + 3 + ... + 100 = %d\n", sum);
return 0;
}
```
2. while循环
```c
#include <stdio.h>
int main() {
int i = 1, sum = 0;
while (i <= 100) {
sum += i;
i++;
}
printf("1 + 2 + 3 + ... + 100 = %d\n", sum);
return 0;
}
```
3. do-while循环
```c
#include <stdio.h>
int main() {
int i = 1, sum = 0;
do {
sum += i;
i++;
} while (i <= 100);
printf("1 + 2 + 3 + ... + 100 = %d\n", sum);
return 0;
}
```
相关问题
c语言:用3种循环分别计算1+2+3+…+100
以下是三种循环分别计算1+2+3+...+100的C语言代码示例:
1. 使用for循环计算[^1]:
```c
int sum = 0;
for (int i = 1; i <= 100; i++) {
sum += i;
}
printf("1+2+3+...+100的总和为:%d\n", sum); // 输出:5050
```
2. 使用while循环计算:
```c
int sum = 0;
int i = 1;
while (i <= 100) {
sum += i;
i++;
}
printf("1+2+3+...+100的总和为:%d\n", sum); // 输出:5050
```
3. 使用do-while循环计算:
```c
int sum = 0;
int i = 1;
do {
sum += i;
i++;
} while (i <= 100);
printf("1+2+3+...+100的总和为:%d\n", sum); // 输出:5050
```
c语言6. 用3种循环分别计算1+2+3+…+100
1. for循环实现:
```c
#include <stdio.h>
int main() {
int i;
for (i = 1; i <= 100; i++) {
printf("%d ", i);
}
return 0;
}
```
2. while循环实现:
```c
#include <stdio.h>
int main() {
int i = 1;
while (i <= 100) {
printf("%d ", i);
i++;
}
return 0;
}
```
3. do-while循环实现:
```c
#include <stdio.h>
int main() {
int i = 1;
do {
printf("%d ", i);
i++;
} while (i <= 100);
return 0;
}
```
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