SELECT t1.*, t2.name FROM dn_policy AS t1 JOIN dn_department AS t2 ON t1.id = t2.id WHERE t1.rebateChannelId = 20 AND t1.createTime BETWEEN UNIX_TIMESTAMP('2023-02-01 00:00:00') AND UNIX_TIMESTAMP('2023-02-28 23:59:59')查不到结果

可能是因为在 dn_policy 表中，rebateChannelId 为 20 的记录在 2023 年 2 月份并不存在，或者在 dn_department 表中，与 dn_policy 表中 rebateChannelId 为 20 的记录关联的 id 也不存在。建议检查数据是否正确或者重新查询。

相关问题

帮我优化如下sql：SELECT T1.quyu, T2.lastNum, T3.jdNum, T4.xcNum FROM (SELECT STREET AS quyu FROM STREET_YXW WHERE 1=1 GROUP BY STREET ) T1 LEFT JOIN ( SELECT T2.STREET_NAME AS quyu,COUNT(*) AS lastNum FROM V_FIRESAFETYREGISTER_DYC T1 LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T2 ON LEFT(T1.HOUSEID,19) = T2.BUILDING_CODE WHERE T1.LASTLOGOUTTIME IS NOT NULL and date_format(T1.LASTLOGOUTTIME,'%Y') = ? GROUP BY T2.STREET_NAME ) T2 ON T1.quyu = T2.quyu LEFT JOIN ( SELECT T3.STREET_NAME AS quyu,COUNT(DISTINCT T1.FIREID) AS jdNum FROM V_SX_FIRESAFETYPLAN T1 LEFT JOIN V_FIRESAFETYREGISTER_DYC T2 ON T1.FIREID = T2.ID LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T3 ON LEFT(T2.HOUSEID,19) = T3.BUILDING_CODE WHERE T1.DATE_NEW IS NOT NULL and date_format(T1.DATE_NEW,'%Y') = ? GROUP BY T3.STREET_NAME ) T3 ON T1.quyu = T3.quyu LEFT JOIN ( SELECT T3.STREET_NAME AS quyu,COUNT(*) as xcNum FROM V_SX_FIRESAFETYTRAINING T1 LEFT JOIN V_FIRESAFETYREGISTER_DYC T2 ON T1.FIREID = T2.ID LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T3 ON LEFT(T2.HOUSEID,19) = T3.BUILDING_CODE WHERE T1.TRAININGTIME IS NOT NULL and date_format(T1.TRAININGTIME,'%Y') = ? GROUP BY T3.STREET_NAME ) T4 ON T1.quyu = T4.quyu ORDER BY T2.lastNum limit ?,?

可以尝试以下优化：

1. 对于子查询中的表，添加合适的索引以提高查询效率；

2. 可以考虑将子查询改为临时表，避免多次重复查询；

3. 在需要排序的字段上添加索引；

4. 尽量避免在 JOIN 条件中使用函数，可以将日期比较条件提取到 WHERE 子句中。

优化后的 SQL 如下：

CREATE TEMPORARY TABLE tmp_street AS
SELECT STREET AS quyu FROM STREET_YXW WHERE 1=1 GROUP BY STREET;

CREATE TEMPORARY TABLE tmp_lastNum AS
SELECT T2.STREET_NAME AS quyu, COUNT(*) AS lastNum
FROM V_FIRESAFETYREGISTER_DYC T1
LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T2 ON LEFT(T1.HOUSEID, 19) = T2.BUILDING_CODE
WHERE T1.LASTLOGOUTTIME IS NOT NULL AND date_format(T1.LASTLOGOUTTIME,'%Y') = ?
GROUP BY T2.STREET_NAME;

CREATE TEMPORARY TABLE tmp_jdNum AS
SELECT T3.STREET_NAME AS quyu, COUNT(DISTINCT T1.FIREID) AS jdNum
FROM V_SX_FIRESAFETYPLAN T1
LEFT JOIN V_FIRESAFETYREGISTER_DYC T2 ON T1.FIREID = T2.ID
LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T3 ON LEFT(T2.HOUSEID, 19) = T3.BUILDING_CODE
WHERE T1.DATE_NEW IS NOT NULL AND date_format(T1.DATE_NEW,'%Y') = ?
GROUP BY T3.STREET_NAME;

CREATE TEMPORARY TABLE tmp_xcNum AS
SELECT T3.STREET_NAME AS quyu, COUNT(*) AS xcNum
FROM V_SX_FIRESAFETYTRAINING T1
LEFT JOIN V_FIRESAFETYREGISTER_DYC T2 ON T1.FIREID = T2.ID
LEFT JOIN V_HSE_COMB_BUILDING_INFO_PA T3 ON LEFT(T2.HOUSEID, 19) = T3.BUILDING_CODE
WHERE T1.TRAININGTIME IS NOT NULL AND date_format(T1.TRAININGTIME,'%Y') = ?
GROUP BY T3.STREET_NAME;

SELECT T1.quyu, T2.lastNum, T3.jdNum, T4.xcNum
FROM tmp_street T1
LEFT JOIN tmp_lastNum T2 ON T1.quyu = T2.quyu
LEFT JOIN tmp_jdNum T3 ON T1.quyu = T3.quyu
LEFT JOIN tmp_xcNum T4 ON T1.quyu = T4.quyu
ORDER BY T2.lastNum
LIMIT ?,?;

请注意，这只是一种可能的优化方案，具体的优化方法还要根据数据库的实际情况进行调整。

SELECT t1.organization_id, t1.organization_name, t1.road_name, SUM( t2.sj_amount ) xfSjAmount, SUM( t2.jl_amount ) xfJlAmount, SUM( t3.xfGeneralSectionAmount ) xfGeneralSectionAmount, SUM( t3.xfGeneralSectionLength ) xfGeneralSectionLength FROM `main_project` t1 LEFT JOIN mat_approval_project t2 ON t2.main_id = t1.id LEFT JOIN ( SELECT project_id, data_type, SUM( money ) xfGeneralSectionAmount, SUM( mileage ) xfGeneralSectionLength FROM mat_project_pavement_approval GROUP BY project_id ) t3 ON t3.project_id = t2.id WHERE t1.project_general_name = '修复性养护' AND t1.project_category_name = '路面工程' AND t1.process_status = '100' AND t3.data_type = '1' AND t1.road_name = '常祁高速' AND t1.project_year = '2023' 这条sql中t1.road_name多条数据只会展示一个，导致根据t1.road_name查询不到数据

这个问题的原因可能是使用了`LEFT JOIN`，导致t1表中的多个记录与t2和t3表中的记录进行了匹配。如果t1表中有多个记录的`t1.road_name`值相同，那么在`SELECT`语句中使用`SUM`函数对t2和t3表中的记录进行了合并，使得最终查询结果中只有一个记录。这可能导致你根据`t1.road_name`无法查到完整的数据。

为了解决这个问题，你可以考虑在`SELECT`语句中增加`t1.road_name`字段，并在`GROUP BY`子句中包含该字段，以确保t1表中的每个记录都能够被正确匹配和展示。例如：

SELECT
  t1.organization_id,
  t1.organization_name,
  t1.road_name,
  SUM(t2.sj_amount) AS xfSjAmount,
  SUM(t2.jl_amount) AS xfJlAmount,
  SUM(t3.xfGeneralSectionAmount) AS xfGeneralSectionAmount,
  SUM(t3.xfGeneralSectionLength) AS xfGeneralSectionLength
FROM
  main_project t1
  LEFT JOIN mat_approval_project t2 ON t2.main_id = t1.id
  LEFT JOIN (
    SELECT
      project_id,
      data_type,
      SUM(money) AS xfGeneralSectionAmount,
      SUM(mileage) AS xfGeneralSectionLength
    FROM
      mat_project_pavement_approval
    GROUP BY
      project_id
  ) t3 ON t3.project_id = t2.id
WHERE
  t1.project_general_name = '修复性养护'
  AND t1.project_category_name = '路面工程'
  AND t1.process_status = '100'
  AND t3.data_type = '1'
  AND t1.road_name = '常祁高速'
  AND t1.project_year = '2023'
GROUP BY
  t1.organization_id,
  t1.organization_name,
  t1.road_name;

这样，就可以确保每个`t1.road_name`值都能够正确地展示在查询结果中。