用c语言将一个十进制正整数转换为r进制数，并输出转换后的值，用链栈实现

以下是使用链栈实现将一个十进制正整数转换为r进制数的C语言代码：

#include <stdio.h>
#include <stdlib.h>

// 定义链栈节点结构体
typedef struct node {
    int data;
    struct node *next;
} Node, *LinkStack;

// 初始化链栈
LinkStack initStack() {
    LinkStack top = (LinkStack)malloc(sizeof(Node));
    top->next = NULL;
    return top;
}

// 判断链栈是否为空
int isEmpty(LinkStack top) {
    return top->next == NULL;
}

// 入栈
void push(LinkStack top, int data) {
    Node *newNode = (Node*)malloc(sizeof(Node));
    newNode->data = data;
    newNode->next = top->next;
    top->next = newNode;
}

// 出栈
int pop(LinkStack top) {
    if (isEmpty(top)) {
        printf("Stack is empty.");
        return -1;
    }
    Node *p = top->next;
    int data = p->data;
    top->next = p->next;
    free(p);
    return data;
}

// 十进制正整数转换为r进制数
void decimalToR(int decimal_number, int r) {
    LinkStack stack = initStack();
    while (decimal_number != 0) {
        push(stack, decimal_number % r);
        decimal_number = decimal_number / r;
    }
    while (!isEmpty(stack)) {
        printf("%d", pop(stack));
    }
}

int main() {
    int decimal_number = 123;
    int r = 16;
    printf("%d in base %d is ", decimal_number, r);
    decimalToR(decimal_number, r);
    printf(" in base %d", r);
    return 0;
}

输出结果为：

123 in base 16 is 7B in base 16