# 将实体之间的关系添加到图形结构中 with driver.session() as session: result7 = session.run("MATCH (a)-[r]->(b) RETURN a.name, type(r), b.name") for record in result7: G.add_edge(record["a.name"], record["b.name"], relation=record["type(r)"])报错:ResultConsumedError: The result has been consumed. Fetch all needed records before calling Result.consume().
时间: 2024-03-05 09:48:07 浏览: 99
这个错误是由于 `result7` 结果集已经被消费(consumed)了,而你尝试对它进行迭代访问。解决方法是先将 `result7` 转换为列表,再对列表进行迭代访问,例如:
```python
with driver.session() as session:
result7 = session.run("MATCH (a)-[r]->(b) RETURN a.name, type(r), b.name")
records = list(result7) # 将结果集转换为列表
for record in records:
G.add_edge(record["a.name"], record["b.name"], relation=record["type(r)"])
```
这样就不会出现 `ResultConsumedError` 错误了。
相关问题
# 从Neo4j数据库中读取实体及其属性 #user实体 with driver.session() as session: result6 = session.run("MATCH (n:level) RETURN n.id as id, n.name as name,n.companion as companion,n.day as day,n.fee as fee,n.play as play,n.time as time").data() # 将实体转换为图形结构 for record in result6: node_id = str(uuid.uuid4()) # 生成 UUID G.add_node(node_id, name=record["name"],companion=record["companion"],day=record["day"],fee=record["fee"],play=record["play"],time=record["time"])创建的图形怎么查看图形中节点的属性列表
要查看图形中节点的属性列表,可以使用NetworkX中的nodes方法。该方法返回一个包含所有节点的列表,然后可以使用Python的for循环遍历所有节点,并使用get_node_attributes方法获取节点的属性字典。以下是一个示例代码:
```python
# 遍历所有节点,获取它们的属性字典
for node in G.nodes():
attributes = nx.get_node_attributes(G, node)
print(node, attributes)
```
在这个代码中,我们首先使用G.nodes()方法获取所有节点的列表,然后使用Python的for循环遍历每个节点。对于每个节点,我们使用nx.get_node_attributes方法获取它的属性字典,并将其打印输出。这样就可以查看图形中节点的属性列表了。
运行# 从Neo4j数据库中读取实体及其属性 with driver.session() as session: result = session.run("MATCH (n:attraction) RETURN n.entity as entity, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat")报错ResultConsumedError: The result has been consumed. Fetch all needed records before calling Result.consume().
这个报错的意思是你在对已经消耗(consumed)完的结果对象进行操作。在使用Neo4j的Python驱动进行查询时,结果对象是一个迭代器,当你使用完这个迭代器后,它就会被自动消耗掉,所以你需要在使用结果之前将所有需要的记录都获取(fetch)到本地,然后再进行操作。
可以在执行查询时,使用 `result = session.run("MATCH (n:attraction) RETURN n.entity as entity, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat").data()` 将结果取出到本地,这样就可以避免这个错误。
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