# 将实体之间的关系添加到图形结构中 with driver.session() as session: result7 = session.run("MATCH (a)-[r]->(b) RETURN a.name, type(r), b.name") for record in result7: G.add_edge(record["a.name"], record["b.name"], relation=record["type(r)"])报错：ResultConsumedError: The result has been consumed. Fetch all needed records before calling Result.consume().

这个错误是由于 `result7` 结果集已经被消费（consumed）了，而你尝试对它进行迭代访问。解决方法是先将 `result7` 转换为列表，再对列表进行迭代访问，例如：

with driver.session() as session:
    result7 = session.run("MATCH (a)-[r]->(b) RETURN a.name, type(r), b.name")
    records = list(result7)  # 将结果集转换为列表
    for record in records:
        G.add_edge(record["a.name"], record["b.name"], relation=record["type(r)"])

这样就不会出现 `ResultConsumedError` 错误了。

相关问题

运行# 从Neo4j数据库中读取实体及其属性 with driver.session() as session: result = session.run("MATCH (n:attraction) RETURN n.entity as entity, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat")报错ResultConsumedError: The result has been consumed. Fetch all needed records before calling Result.consume().

这个报错的意思是你在对已经消耗（consumed）完的结果对象进行操作。在使用Neo4j的Python驱动进行查询时，结果对象是一个迭代器，当你使用完这个迭代器后，它就会被自动消耗掉，所以你需要在使用结果之前将所有需要的记录都获取（fetch）到本地，然后再进行操作。

可以在执行查询时，使用 `result = session.run("MATCH (n:attraction) RETURN n.entity as entity, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat").data()` 将结果取出到本地，这样就可以避免这个错误。

driver = GraphDatabase.driver("neo4j://localhost:7687") # 从Neo4j数据库中读取实体及其属性 #景点实体 with driver.session() as session: result = session.run("MATCH (n:attraction) RETURN n.id as id, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat").data() # 将实体转换为图形结构 G = nx.Graph() for record in result: node_id = str(uuid.uuid4()) G.add_node(node_id, name=record["name"], time_reference=record["time_reference"], address=record["address"],open_time=record["open_time"],ticket=record["ticket"],region=record["region"],lon=record["lon"],lat=record["lat"])attributes = nx.get_node_attributes(G, node_id) attributes为什么输出实体属性是空值

在你的代码中，变量node_id在每次迭代时都被重新赋值为新的uuid.uuid4()，这就导致了每个节点的id都是唯一的，但是你只能获取最后一个节点的属性，因为在最后一次迭代后，node_id被赋值为最后一个节点的id。因此，当你在使用nx.get_node_attributes（）方法时，只能获取最后一个节点的属性，其他节点的属性将无法获取。要解决这个问题，你需要在添加节点时将node_id与节点属性关联起来，可以使用一个字典来存储节点id和属性的键值对，这样就可以根据节点id获取其属性了。以下是修改后的代码示例：

driver = GraphDatabase.driver("neo4j://localhost:7687") 
# 从Neo4j数据库中读取实体及其属性 #景点实体 
with driver.session() as session:     
    result = session.run("MATCH (n:attraction) RETURN n.id as id, n.name as name, n.time_reference as time_reference, n.address as address, n.open_time as open_time, n.ticket as ticket, n.region as region, n.lon as lon,n.lat as lat").data()   
    # 将实体转换为图形结构 
    G = nx.Graph()
    node_attr_dict = {} # 存储节点属性的字典
    for record in result:     
        node_id = str(uuid.uuid4())      
        G.add_node(node_id) # 添加节点
        node_attr_dict[node_id] = {'name': record["name"], 'time_reference': record["time_reference"], 'address': record["address"], 'open_time': record["open_time"], 'ticket': record["ticket"], 'region': record["region"], 'lon': record["lon"], 'lat': record["lat"]} # 存储节点属性
    nx.set_node_attributes(G, node_attr_dict) # 将节点属性与图关联起来

attributes = nx.get_node_attributes(G, node_id)

这样，你就可以通过节点id获取其属性了。