用c语言制作2048小游戏
时间: 2023-09-12 11:08:21 浏览: 96
好的,制作2048小游戏的基本思路如下:
1. 定义游戏界面:可以使用二维数组来表示游戏面板,每个元素表示该位置上的数字。
2. 定义游戏逻辑:根据玩家的操作,移动数字并合并相同数字。
3. 定义游戏结束条件:当游戏面板填满且无法继续合并数字时,游戏结束。
下面是一个简单的C语言实现:
```
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROW 4
#define COL 4
// 游戏界面
int board[ROW][COL];
// 初始化游戏界面
void init_board() {
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
board[i][j] = 0;
}
}
}
// 在空白位置上随机生成数字
void generate_number() {
int i, j;
int count = 0;
int empty_pos[ROW * COL][2];
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
if (board[i][j] == 0) {
empty_pos[count][0] = i;
empty_pos[count][1] = j;
count++;
}
}
}
if (count == 0) {
return;
}
int pos = rand() % count;
int value = (rand() % 2 + 1) * 2; // 随机生成2或4
board[empty_pos[pos][0]][empty_pos[pos][1]] = value;
}
// 移动数字
void move(int x1, int y1, int x2, int y2) {
if (board[x2][y2] == 0) {
board[x2][y2] = board[x1][y1];
board[x1][y1] = 0;
} else if (board[x2][y2] == board[x1][y1]) {
board[x2][y2] *= 2;
board[x1][y1] = 0;
}
}
// 向上移动数字
void move_up() {
int i, j, k;
for (j = 0; j < COL; j++) {
k = 0;
for (i = 1; i < ROW; i++) {
if (board[i][j] != 0) {
for (; k < i; k++) {
if (board[k][j] == 0) {
move(i, j, k, j);
break;
} else if (board[k][j] == board[i][j]) {
move(i, j, k, j);
k++;
break;
}
}
}
}
}
}
// 向下移动数字
void move_down() {
int i, j, k;
for (j = 0; j < COL; j++) {
k = ROW - 1;
for (i = ROW - 2; i >= 0; i--) {
if (board[i][j] != 0) {
for (; k > i; k--) {
if (board[k][j] == 0) {
move(i, j, k, j);
break;
} else if (board[k][j] == board[i][j]) {
move(i, j, k, j);
k--;
break;
}
}
}
}
}
}
// 向左移动数字
void move_left() {
int i, j, k;
for (i = 0; i < ROW; i++) {
k = 0;
for (j = 1; j < COL; j++) {
if (board[i][j] != 0) {
for (; k < j; k++) {
if (board[i][k] == 0) {
move(i, j, i, k);
break;
} else if (board[i][k] == board[i][j]) {
move(i, j, i, k);
k++;
break;
}
}
}
}
}
}
// 向右移动数字
void move_right() {
int i, j, k;
for (i = 0; i < ROW; i++) {
k = COL - 1;
for (j = COL - 2; j >= 0; j--) {
if (board[i][j] != 0) {
for (; k > j; k--) {
if (board[i][k] == 0) {
move(i, j, i, k);
break;
} else if (board[i][k] == board[i][j]) {
move(i, j, i, k);
k--;
break;
}
}
}
}
}
}
// 判断游戏是否结束
int is_game_over() {
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
if (board[i][j] == 0) {
return 0;
}
if (i > 0 && board[i][j] == board[i-1][j]) {
return 0;
}
if (j > 0 && board[i][j] == board[i][j-1]) {
return 0;
}
}
}
return 1;
}
// 打印游戏界面
void print_board() {
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
printf("%d\t", board[i][j]);
}
printf("\n");
}
}
int main() {
srand(time(NULL)); // 随机数种子
init_board();
generate_number();
generate_number();
print_board();
while (!is_game_over()) {
char c = getchar();
switch (c) {
case 'w':
move_up();
break;
case 's':
move_down();
break;
case 'a':
move_left();
break;
case 'd':
move_right();
break;
default:
continue;
}
generate_number();
print_board();
}
printf("Game over!\n");
return 0;
}
```
以上是一个简单的2048游戏的C语言实现,代码中可能存在一些问题,仅供参考。
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