Find errors: void g() { cout << "Inside function g" << endl; void h() { cout << "Inside function h" << endl; } } int sum(int x, int y) { int result{0}; result = x + y; } float cube(float); // function prototype cube(float number) // function definition { return number * number * number; }
时间: 2024-02-14 10:05:37 浏览: 27
There are several errors in the given code snippets:
1. The function `h` is defined inside another function `g`, which is not allowed in C++. Functions can only be defined outside of other functions or inside a class as a member function.
2. The function `sum` does not have a return statement, even though it is declared to return an `int`. This will cause a compilation error if the function is called.
3. The function `cube` is missing the return type in its definition. It should be `float cube(float number)` instead of `cube(float number)`.
Here is the corrected code:
```
// Corrected code
#include <iostream>
void h() {
std::cout << "Inside function h" << std::endl;
}
void g() {
std::cout << "Inside function g" << std::endl;
h();
}
int sum(int x, int y) {
int result{0};
result = x + y;
return result;
}
float cube(float number) {
return number * number * number;
}
int main() {
g();
std::cout << sum(3, 4) << std::endl;
std::cout << cube(2.5) << std::endl;
return 0;
}
```
This code defines the functions `h`, `g`, `sum`, and `cube`, and corrects the errors mentioned above. The `main` function calls `g`, `sum`, and `cube` and outputs their results.