def show(chessboard): for i in range(len(chessboard)): mark = ' ' row = chessboard[i] for j in row: mark = mark + tag[j + 1] + ' ' print(mark)存在什么问题
时间: 2024-02-05 19:03:12 浏览: 28
代码缺少了一个缩进,应该修改为:
```python
def show(chessboard):
for i in range(len(chessboard)):
mark = ' '
row = chessboard[i]
for j in row:
mark = mark + tag[j + 1] + ' '
print(mark)
```
这样就可以正确地打印出棋盘了。
相关问题
Uncaught TypeError: chessboard.getContext is not a function
This error occurs when you try to call the getContext() method on a variable that is not a canvas element.
To fix this error, make sure that the variable chessboard is a reference to a canvas element. You can check if chessboard is a canvas element by using the instanceof operator:
if (chessboard instanceof HTMLCanvasElement) {
// chessboard is a canvas element
var context = chessboard.getContext('2d');
// use the canvas context here
} else {
// chessboard is not a canvas element
console.error('chessboard is not a canvas element');
}
def terminal(chessboard, win, position): for line in win: m1,n1 = position[line[0]][0],position[line[0]][1] m2,n2 = position[line[1]][0],position[line[1]][1] m3,n3 = position[line[2]][0],position[line[2]][1] if chessboard[m1][n1] == chessboard[m2][n2] == chessboard[m3][n3] == -1: return -1 elif chessboard[m1][n1] == chessboard[m2][n2] == chessboard[m3][n3] == 1: return 1 return 0存在什么问题
这段代码没有语法错误,但是在语义上存在问题。
`terminal` 函数的作用是判断当前棋局是否已经结束,如果结束,则返回胜者;如果没有结束,则返回 0。
在这段代码中,当胜利条件满足时,返回的是 1,而不是胜者的标志。同样,当失败条件满足时,返回的是 -1,而不是失败者的标志。
修改后的代码如下:
```python
def terminal(chessboard, win, position):
for line in win:
m1,n1 = position[line[0]][0],position[line[0]][1]
m2,n2 = position[line[1]][0],position[line[1]][1]
m3,n3 = position[line[2]][0],position[line[2]][1]
if chessboard[m1][n1] == chessboard[m2][n2] == chessboard[m3][n3] == -1:
return 'O'
elif chessboard[m1][n1] == chessboard[m2][n2] == chessboard[m3][n3] == 1:
return 'X'
return 0
```
这样修改后,当胜利条件满足时,`terminal` 函数返回胜利者的标志,即 'O' 或 'X'。当失败条件满足时,返回的是 0,表示游戏还没有结束。