(1)查询选修课程号为C01，并且成绩及格的学生学号、姓名和系别名称。 (2)查询计算机学院选修C03课程的学生姓名、课程名称以及这门课程的成绩。(3)在Reports表中查询至少选修课了程号为C01和C02的学生学号和姓名。(4)查询既没有选修课程号C01，也没有选修课程号C02的学生的学号和姓名。(5) 查询每个同学基本信息及其选修课程的情况。(6)查询每个学生及其选修课程的情况(若某一个学生没有选课，只输出学生的基本情况信息，其选课信息为空值)。 (7)查询选修了课程名为“GIS开发”的学生学号和姓名。(8) 查询没有选修C02课程的学生学号和姓名。 (9)查询所有课程成绩均大于90分的学生学号和姓名。(10)查询选修了4门及以上课程的学生的学号、姓名和选修课程数。(11) 查询选修全部课程的学生姓名，相当于查询这样的学生，没有一门课程是他不选的。 (12) 查询平均成绩大于等于黄河同学的平均成绩的学生的学号、姓名和平均成绩。(13)查询每门课程获得最高分的同学的学号、姓名、课程名称和成绩，并按照最高成绩从高到低进行排序。

很好，您的问题是关于 SQL 语句的。以下是您提出的问题的 SQL 查询语句：

(1)查询选修课程号为C01，并且成绩及格的学生学号、姓名和系别名称。

SELECT StudentID, StudentName, DepartmentName
FROM Student, Department, SC
WHERE Student.StudentID = SC.StudentID
AND SC.CourseID = 'C01'
AND SC.Score >= 60
AND Student.DepartmentID = Department.DepartmentID;

(2)查询计算机学院选修C03课程的学生姓名、课程名称以及这门课程的成绩。

SELECT StudentName, CourseName, Score
FROM Student, Course, SC, Department
WHERE Student.StudentID = SC.StudentID
AND Course.CourseID = SC.CourseID
AND Department.DepartmentID = Student.DepartmentID
AND Department.DepartmentName = '计算机学院'
AND Course.CourseID = 'C03';

(3)在Reports表中查询至少选修课了程号为C01和C02的学生学号和姓名。

SELECT StudentID, StudentName
FROM Reports
WHERE CourseID IN ('C01','C02')
GROUP BY StudentID, StudentName
HAVING COUNT(DISTINCT CourseID) >= 2;

(4)查询既没有选修课程号C01，也没有选修课程号C02的学生的学号和姓名。

SELECT StudentID, StudentName
FROM Student
WHERE StudentID NOT IN (
    SELECT StudentID
    FROM SC
    WHERE CourseID IN ('C01','C02')
);

(5)查询每个同学基本信息及其选修课程的情况。

SELECT Student.StudentID, Student.StudentName, Student.Gender, Student.Birthday, Student.Address, Department.DepartmentName, SC.CourseID, Course.CourseName, SC.Score
FROM Student
LEFT JOIN SC ON Student.StudentID = SC.StudentID
LEFT JOIN Course ON SC.CourseID = Course.CourseID
LEFT JOIN Department ON Student.DepartmentID = Department.DepartmentID
ORDER BY Student.StudentID, SC.CourseID;

(6)查询每个学生及其选修课程的情况(若某一个学生没有选课，只输出学生的基本情况信息，其选课信息为空值)。

SELECT Student.StudentID, Student.StudentName, Student.Gender, Student.Birthday, Student.Address, Department.DepartmentName, SC.CourseID, Course.CourseName, SC.Score
FROM Student
LEFT JOIN SC ON Student.StudentID = SC.StudentID
LEFT JOIN Course ON SC.CourseID = Course.CourseID
LEFT JOIN Department ON Student.DepartmentID = Department.DepartmentID
ORDER BY Student.StudentID, SC.CourseID;

(7)查询选修了课程名为“GIS开发”的学生学号和姓名。

SELECT Student.StudentID, Student.StudentName
FROM Student, SC, Course
WHERE Student.StudentID = SC.StudentID
AND SC.CourseID = Course.CourseID
AND Course.CourseName = 'GIS开发';

(8)查询没有选修C02课程的学生学号和姓名。

SELECT Student.StudentID, Student.StudentName
FROM Student
WHERE Student.StudentID NOT IN (
    SELECT StudentID
    FROM SC
    WHERE CourseID = 'C02'
);

(9)查询所有课程成绩均大于90分的学生学号和姓名。

SELECT StudentID, StudentName
FROM SC, Student
WHERE SC.StudentID = Student.StudentID
AND Score >= 90
GROUP BY StudentID, StudentName
HAVING COUNT(DISTINCT CourseID) = (
    SELECT COUNT(DISTINCT CourseID)
    FROM Course
);

(10)查询选修了4门及以上课程的学生的学号、姓名和选修课程数。

SELECT StudentID, StudentName, COUNT(*) AS CourseCount
FROM SC, Student
WHERE SC.StudentID = Student.StudentID
GROUP BY StudentID, StudentName
HAVING COUNT(*) >= 4;

(11)查询选修全部课程的学生姓名，相当于查询这样的学生，没有一门课程是他不选的。

SELECT Student.StudentName
FROM Student
WHERE NOT EXISTS (
    SELECT CourseID
    FROM Course
    WHERE NOT EXISTS (
        SELECT SC.StudentID
        FROM SC
        WHERE SC.StudentID = Student.StudentID
        AND SC.CourseID = Course.CourseID
    )
);

(12)查询平均成绩大于等于黄河同学的平均成绩的学生的学号、姓名和平均成绩。

SELECT AVG(SC.Score) AS AvgScore, Student.StudentID, Student.StudentName
FROM SC, Student
WHERE SC.StudentID = Student.StudentID
GROUP BY Student.StudentID, Student.StudentName
HAVING AVG(SC.Score) >= (
    SELECT AVG(SC.Score)
    FROM SC, Student
    WHERE SC.StudentID = Student.StudentID
    AND Student.StudentName = '黄河'
);

(13)查询每门课程获得最高分的同学的学号、姓名、课程名称和成绩，并按照最高成绩从高到低进行排序。

SELECT SC.StudentID, Student.StudentName, Course.CourseName, MAX(SC.Score) AS MaxScore
FROM SC, Student, Course
WHERE SC.StudentID = Student.StudentID
AND SC.CourseID = Course.CourseID
GROUP BY SC.CourseID
ORDER BY MaxScore DESC;