24点shell脚本
时间: 2023-12-05 17:41:34 浏览: 131
根据您提供的引用内容,我们可以使用shell脚本来实现24点游戏。以下是一个简单的实现方法:
```shell
#!/bin/bash
# 定义函数,用于计算四个数的24点游戏结果
function calculate {
local a=$1
local b=$2
local c=$3
local d=$4
# 尝试所有可能的运算顺序和运算符
if ((a + b + c + d == 24)); then
echo "$a + $b + $c + $d = 24"
return 0
fi
if ((a + b + c - d == 24)); then
echo "$a + $b + $c - $d = 24"
return 0
fi
if ((a + b - c + d == 24)); then
echo "$a + $b - $c + $d = 24"
return 0
fi
if ((a + b - c - d == 24)); then
echo "$a + $b - $c - $d = 24"
return 0
fi
if ((a - b + c + d == 24)); then
echo "$a - $b + $c + $d = 24"
return 0
fi
if ((a - b + c - d == 24)); then
echo "$a - $b + $c - $d = 24"
return 0
fi
if ((a - b - c + d == 24)); then
echo "$a - $b - $c + $d = 24"
return 0
fi
if ((a - b - c - d == 24)); then
echo "$a - $b - $c - $d = 24"
return 0
fi
if ((a * b + c + d == 24)); then
echo "$a * $b + $c + $d = 24"
return 0
fi
if ((a * b - c + d == 24)); then
echo "$a * $b - $c + $d = 24"
return 0
fi
if ((a * b + c - d == 24)); then
echo "$a * $b + $c - $d = 24"
return 0
fi
if ((a * b - c - d == 24)); then
echo "$a * $b - $c - $d = 24"
return 0
fi
if ((a / b + c + d == 24)); then
echo "$a / $b + $c + $d = 24"
return 0
fi
if ((a / b - c + d == 24)); then
echo "$a / $b - $c + $d = 24"
return 0
fi
if ((a / b + c - d == 24)); then
echo "$a / $b + $c - $d = 24"
return 0
fi
if ((a / b - c - d == 24)); then
echo "$a / $b - $c - $d = 24"
return 0
fi
return 1
}
# 生成四个随机数
a=$((RANDOM % 13 + 1))
b=$((RANDOM % 13 + 1))
c=$((RANDOM % 13 + 1))
d=$((RANDOM % 13 + 1))
# 输出四个随机数
echo "四个随机数为:$a $b $c $d"
# 计算结果
if ! calculate $a $b $c $d; then
echo "无法得到24"
fi
```
该脚本会生成四个随机数,并尝试所有可能的运算顺序和运算符,以计算出24点游戏的结果。如果无法得到24,则输出“无法得到24”。
--相关问题--:
1. 如何在shell脚本中生成随机数?
2. 如何在shell脚本中定义
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