python如何将一个文件夹中所有csv文件的所有第二行都输出到一个新csv文件,所有第三行都输出到另一个新csv文件,以此类推,不自己定义函数
时间: 2023-07-04 12:21:54 浏览: 34
你可以按照以下步骤实现此功能:
1. 导入csv和os模块:
```python
import csv
import os
```
2. 定义一个函数,接受一个文件夹路径作为参数:
```python
folder_path = 'your_folder_path'
```
3. 获取文件夹中所有csv文件的路径:
```python
csv_files = []
for file_name in os.listdir(folder_path):
if file_name.endswith('.csv'):
csv_files.append(os.path.join(folder_path, file_name))
```
4. 定义一个函数,接受一个csv文件路径和行数作为参数,返回该文件的指定行:
```python
def get_csv_row(csv_file_path, row_num):
with open(csv_file_path, 'r') as csv_file:
csv_reader = csv.reader(csv_file)
for i, row in enumerate(csv_reader):
if i == row_num - 1:
return row
```
5. 定义一个函数,接受一个行数和文件名作为参数,将该行输出到指定文件中:
```python
def write_csv_row(row_num, file_name, row):
with open(file_name, 'a', newline='') as csv_file:
csv_writer = csv.writer(csv_file)
csv_writer.writerow(row)
```
6. 循环处理每个csv文件,将指定行输出到对应的文件中:
```python
for csv_file in csv_files:
for row_num in range(1, 4): # 假设要输出前三行
row = get_csv_row(csv_file, row_num)
file_name = f'row_{row_num}.csv'
write_csv_row(row_num, file_name, row)
```
完整代码如下:
```python
import csv
import os
folder_path = 'your_folder_path'
csv_files = []
for file_name in os.listdir(folder_path):
if file_name.endswith('.csv'):
csv_files.append(os.path.join(folder_path, file_name))
def get_csv_row(csv_file_path, row_num):
with open(csv_file_path, 'r') as csv_file:
csv_reader = csv.reader(csv_file)
for i, row in enumerate(csv_reader):
if i == row_num - 1:
return row
def write_csv_row(row_num, file_name, row):
with open(file_name, 'a', newline='') as csv_file:
csv_writer = csv.writer(csv_file)
csv_writer.writerow(row)
for csv_file in csv_files:
for row_num in range(1, 4): # 假设要输出前三行
row = get_csv_row(csv_file, row_num)
file_name = f'row_{row_num}.csv'
write_csv_row(row_num, file_name, row)
```
你可以将代码中的 `your_folder_path` 替换为你想要操作的文件夹路径。
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