编写函数，判断一条直线和圆的位置关系，调用Python中的画布(inter库)，并将位置关系的结果显示在画布上

在Python中，你可以结合`PIL`（Python Imaging Library）或`matplotlib`库来绘制图像，并利用`Shapely`库来处理几何形状的关系。下面是一个简单的例子，展示如何编写一个函数，判断直线和圆的位置关系，并在`Tkinter`的`Canvas`上显示结果：

from tkinter import Tk, Canvas
from tkinter import messagebox as msgbox
from PIL import Image, ImageDraw
import shapely.geometry as sg

def draw_circle_and_line(circle_center, circle_radius, line_points):
    img = Image.new('RGB', (400, 400), 'white')
    draw = ImageDraw.Draw(img)
    
    circle = sg.Point(*circle_center).buffer(circle_radius)
    line = sg.LineString(line_points)

    if shapely.ops.intersects(line, circle):
        intersection = list(circle.intersection(line))
        result = "直线和圆相交"
        color = 'red'  # 表示红色区域
    elif line.distance(circle) == circle_radius:  # 相切
        result = "直线和圆相切"
        color = 'blue'
    else:  # 相离
        result = "直线和圆相离"
        color = 'green'

    for point in intersection:
        draw.point(point.coords[0], fill=color)

    canvas.create_image(0, 0, anchor="nw", image=img)
    msgbox.showinfo("位置关系", result)

# 示例参数
circle_center = (200, 200)
circle_radius = 50
line_points = [(50, 50), (350, 350)]

root = Tk()
canvas = Canvas(root, width=400, height=400)
canvas.pack()

draw_circle_and_line(circle_center, circle_radius, line_points)
root.mainloop()