用turtle库递归算法实现正方形分割
时间: 2024-03-20 13:16:46 浏览: 66
好的,下面是用turtle库递归算法实现正方形分割的代码:
```python
import turtle
def draw_square(length, depth):
if depth == 0:
return
turtle.forward(length/2)
turtle.left(90)
turtle.forward(length/2)
turtle.right(90)
turtle.color("red")
turtle.begin_fill()
for i in range(4):
turtle.forward(length)
turtle.left(90)
turtle.end_fill()
turtle.left(90)
turtle.forward(length/2)
turtle.right(90)
draw_square(length/2, depth-1)
turtle.right(90)
turtle.forward(length)
turtle.left(90)
draw_square(length/2, depth-1)
turtle.left(90)
turtle.forward(length/2)
turtle.right(90)
draw_square(length/2, depth-1)
turtle.right(90)
turtle.forward(length)
turtle.left(90)
draw_square(length/2, depth-1)
turtle.left(90)
turtle.forward(length/2)
turtle.right(90)
turtle.color("white")
turtle.begin_fill()
for i in range(4):
turtle.forward(length)
turtle.left(90)
turtle.end_fill()
turtle.right(90)
turtle.penup()
turtle.forward(length/2)
turtle.pendown()
turtle.speed(0)
draw_square(200, 4)
turtle.done()
```
这个函数`draw_square`的参数是正方形的边长和递归的深度。在每次递归中,首先绘制正方形的左下角,然后绘制大正方形的下一层4个小正方形,最后回到起点。在递归的过程中,每次将正方形的边长减半,深度减1,直到深度为0时结束递归。
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