用C语言的循环语句求解斐波那契数列的前40项

#include <stdio.h>

int main() {
    int n = 40;
    int fib1 = 0, fib2 = 1;
    printf("%d %d ", fib1, fib2);
    for(int i = 3; i <= n; i++) {
        int fib3 = fib1 + fib2;
        printf("%d ", fib3);
        fib1 = fib2;
        fib2 = fib3;
    }
    return 0;
}