基于gmp调用的RSA3072的C++实现
时间: 2024-03-19 18:45:04 浏览: 49
以下是基于GMP调用的RSA3072的C++实现示例代码:
```C++
#include <iostream>
#include <gmpxx.h>
using namespace std;
int main() {
// Generate random prime numbers
mpz_class p, q;
gmp_randstate_t state;
gmp_randinit_default(state);
gmp_randseed_ui(state, time(NULL));
mpz_urandomb(p.get_mpz_t(), state, 1024);
mpz_nextprime(p.get_mpz_t(), p.get_mpz_t());
mpz_urandomb(q.get_mpz_t(), state, 1024);
mpz_nextprime(q.get_mpz_t(), q.get_mpz_t());
// Calculate n and phi(n)
mpz_class n = p * q;
mpz_class phi_n = (p - 1) * (q - 1);
// Generate random e
mpz_class e;
do {
mpz_urandomb(e.get_mpz_t(), state, 1024);
mpz_nextprime(e.get_mpz_t(), e.get_mpz_t());
} while (mpz_cmp(e.get_mpz_t(), phi_n.get_mpz_t()) >= 0);
// Calculate d
mpz_class d;
mpz_invert(d.get_mpz_t(), e.get_mpz_t(), phi_n.get_mpz_t());
// Print keys
cout << "Public key (n, e): (" << n << ", " << e << ")" << endl;
cout << "Private key (n, d): (" << n << ", " << d << ")" << endl;
// Encrypt and decrypt a message
mpz_class m = 123456789;
mpz_class c, m_decrypted;
mpz_powm(c.get_mpz_t(), m.get_mpz_t(), e.get_mpz_t(), n.get_mpz_t());
mpz_powm(m_decrypted.get_mpz_t(), c.get_mpz_t(), d.get_mpz_t(), n.get_mpz_t());
cout << "Encrypted message: " << c << endl;
cout << "Decrypted message: " << m_decrypted << endl;
return 0;
}
```
这段代码使用了GMP库生成RSA3072的公私钥,并且进行了一个简单的加密和解密操作。在实际使用时,需要注意安全性和性能等方面的问题。
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