阅读下面的程序: class StringDemo{ public static void main(String[]args){ String s1=“a"; String s2=“b"; show(s1,s2); System.out.printIns1+s2); public static void show(String s1,String s2){ s1=s1+”q”; s2=s2+s1; 上述程序的运行结果为() A、ab B、aqb C.agbaq D.aqaqb

该程序有语法错误，正确的程序如下：

class StringDemo {
    public static void main(String[] args) {
        String s1 = "a";
        String s2 = "b";
        show(s1, s2);
        System.out.println(s1 + s2);
    }

    public static void show(String s1, String s2) {
        s1 = s1 + "q";
        s2 = s2 + s1;
        System.out.println(s2);
    }
}

运行结果为 C、agbaq。

相关问题

public class Test{ public static void main(String[] args){ String s1 = "runoob"; String s2 = "runoob"; System.out.println("s1 == s2 is:" + s1 == s2);}}

The code you provided has a small mistake in the print statement. The expression `"s1 == s2 is:" + s1` is concatenated with `== s2` before being passed to `System.out.println()`. This causes a compilation error because you cannot concatenate a string with a boolean value directly.

To fix this, you need to use parentheses to group the concatenation expression properly. Here's the corrected code:

public class Test {
    public static void main(String[] args) {
        String s1 = "runoob";
        String s2 = "runoob";
        System.out.println("s1 == s2 is: " + (s1 == s2));
    }
}

In this corrected code, the expression `(s1 == s2)` is properly grouped and then concatenated with the string `"s1 == s2 is: "`.

public class stringT { ​public static void main(String[] args) { ​​String s1 = "Hello"; String s2 = "World"System.out.println(s1.equals(s2))

您的代码有语法错误，缺少分号和右括号。正确的代码如下：

public class stringT { 
    public static void main(String[] args) { 
        String s1 = "Hello"; 
        String s2 = "World";
        System.out.println(s1.equals(s2));
    }
}

这段代码会输出 `false`，因为 `s1` 和 `s2` 的值不相等。如果您想要比较两个字符串是否相等，可以使用 `equals()` 方法。