井字棋python简单

井字棋（Tic-Tac-Toe）是一种简单的双人游戏，通常是在3x3的网格上进行。玩家轮流在空格中放置自己的标记（通常是“X”和“O”），第一个在水平线、垂直线或对角线上排列成一线的玩家获胜。如果所有的格子都被填满，而没有玩家形成一线，则游戏以平局结束。

以下是一个简单的Python实现井字棋的示例代码：

def print_board(board):
    for row in board:
        print(" | ".join(row))
        print("-" * 5)

def check_winner(board, player):
    for row in board:
        if all([spot == player for spot in row]):
            return True
    for col in range(3):
        if all([board[row][col] == player for row in range(3)]):
            return True
    if all([board[i][i] == player for i in range(3)]) or all([board[i][2 - i] == player for i in range(3)]):
        return True
    return False

def get_move(player):
    while True:
        try:
            move = int(input(f"Player {player}, enter your move (1-9): ")) - 1
            if move >= 0 and move < 9:
                return move
            else:
                print("Invalid move. Please try again.")
        except ValueError:
            print("Invalid move. Please enter a number.")

def play_game():
    board = [[" " for _ in range(3)] for _ in range(3)]
    current_player = "X"
    
    while True:
        print_board(board)
        move = get_move(current_player)
        row, col = divmod(move, 3)
        
        if board[row][col] == " ":
            board[row][col] = current_player
        else:
            print("This spot is already taken. Please choose another one.")
            continue
        
        if check_winner(board, current_player):
            print_board(board)
            print(f"Player {current_player} wins!")
            break
        
        if all(all(cell != " " for cell in row) for row in board):
            print_board(board)
            print("It's a tie!")
            break
        
        current_player = "O" if current_player == "X" else "X"

play_game()

在这段代码中，我们定义了一个简单的井字棋游戏，其中包括了打印棋盘、检查获胜条件、获取玩家移动和主游戏循环的函数。游戏会在控制台中进行，玩家需要输入1到9的数字来选择放置标记的位置。