银行家算法用c语言模拟实现
时间: 2024-01-14 22:19:10 浏览: 73
以下是使用C语言实现银行家算法的代码示例:
```c
#include <stdio.h>
#include <stdbool.h>
#define MAX_PROCESS 10
#define MAX_RESOURCE 10
int available[MAX_RESOURCE];
int max[MAX_PROCESS][MAX_RESOURCE];
int allocation[MAX_PROCESS][MAX_RESOURCE];
int need[MAX_PROCESS][MAX_RESOURCE];
bool finish[MAX_PROCESS];
int num_process, num_resource;
void init() {
printf("请输入进程数和资源数:");
scanf("%d%d", &num_process, &num_resource);
printf("请输入每个资源的数量:");
for (int i = 0; i < num_resource; i++) {
scanf("%d", &available[i]);
}
printf("请输入每个进程已分配的资源数量:\n");
for (int i = 0; i < num_process; i++) {
printf("进程 %d:", i);
for (int j = 0; j < num_resource; j++) {
scanf("%d", &allocation[i][j]);
}
}
printf("请输入每个进程最大的资源需求量:\n");
for (int i = 0; i < num_process; i++) {
printf("进程 %d:", i);
for (int j = 0; j < num_resource; j++) {
scanf("%d", &max[i][j]);
need[i][j] = max[i][j] - allocation[i][j];
}
}
}
bool check(int process) {
for (int i = 0; i < num_resource; i++) {
if (need[process][i] > available[i]) {
return false;
}
}
return true;
}
void release(int process) {
for (int i = 0; i < num_resource; i++) {
available[i] += allocation[process][i];
allocation[process][i] = 0;
need[process][i] = 0;
}
finish[process] = true;
}
void banker() {
int count = 0;
bool flag = true;
while (count < num_process) {
flag = true;
for (int i = 0; i < num_process; i++) {
if (!finish[i] && check(i)) {
release(i);
printf("进程 %d 执行完毕\n", i);
count++;
flag = false;
}
}
if (flag) {
printf("系统处于不安全状态,无法分配资源\n");
break;
}
}
if (count == num_process) {
printf("系统处于安全状态,可以分配资源\n");
}
}
int main() {
init();
banker();
return 0;
}
```
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