java实现paxos算法

下面是一个简单的Java实现Paxos算法的示例代码：

import java.util.HashMap;
import java.util.Map;

class Paxos {
    private int numAcceptors;
    private int majority;
    private Map<Integer, Integer> acceptorResponses;

    public Paxos(int numAcceptors) {
        this.numAcceptors = numAcceptors;
        this.majority = numAcceptors / 2 + 1;
        this.acceptorResponses = new HashMap<>();
    }

    public int runPaxos(int proposal) {
        int acceptedProposal = -1;
        int count = 0;

        while (count < majority) {
            // Phase 1: Prepare
            for (int i = 0; i < numAcceptors; i++) {
                int response = sendPrepare(i, proposal);
                if (response != -1) {
                    acceptorResponses.put(i, response);
                }
            }

            // Phase 2: Accept
            int maxProposal = -1;
            int maxProposalResponse = -1;

            for (int response : acceptorResponses.values()) {
                if (response > maxProposalResponse) {
                    maxProposalResponse = response;
                    maxProposal = response;
                }
            }

            if (maxProposal != -1) {
                acceptedProposal = maxProposal;
                count++;
            } else {
                proposal++;
            }
        }

        return acceptedProposal;
    }

    private int sendPrepare(int acceptorId, int proposal) {
        // 发送准备请求给acceptorId，获取来自acceptorId的响应
        // 返回acceptorId响应的proposal，如果没有响应，则返回-1
        return -1;
    }
}

public class Main {
    public static void main(String[] args) {
        Paxos paxos = new Paxos(5);
        int proposal = 1;
        int acceptedProposal = paxos.runPaxos(proposal);
        System.out.println("Accepted proposal: " + acceptedProposal);
    }
}

请注意，这只是一个简单的Paxos算法实现示例，实际的Paxos算法可能更加复杂。在这个示例中，我们假设已经实现了`sendPrepare`方法来发送准备请求并接收来自acceptor的响应。在实际应用中，还需要考虑消息传递、网络通信、故障处理等其他方面的实现细节。