java奇数九宫格自动填充
时间: 2023-11-10 08:03:00 浏览: 187
可以使用回溯法实现Java奇数九宫格的自动填充。具体实现思路如下:
1. 定义一个二维数组作为九宫格的模板,初始化为0;
2. 从第一行第一列开始,依次尝试填入数字1-9;
3. 每填入一个数字,检查当前行、当前列和当前宫(3x3的小方格)是否已经有重复的数字;
4. 如果没有重复的数字,则继续向下一格填入数字;如果有重复的数字,则回溯到上一格重新填入数字;
5. 当填满最后一格时,输出结果。
下面是Java代码实现示例:
```
public class OddMagicSquare {
private static final int GRID_SIZE = 3;
private boolean isMagicSquare(int[][] grid) {
int magicNum = (GRID_SIZE * (GRID_SIZE * GRID_SIZE + 1)) / 2;
// 检查每一行
for (int i = 0; i < GRID_SIZE; i++) {
int sum = 0;
for (int j = 0; j < GRID_SIZE; j++) {
sum += grid[i][j];
}
if (sum != magicNum) {
return false;
}
}
// 检查每一列
for (int i = 0; i < GRID_SIZE; i++) {
int sum = 0;
for (int j = 0; j < GRID_SIZE; j++) {
sum += grid[j][i];
}
if (sum != magicNum) {
return false;
}
}
// 检查对角线
int sum = 0;
for (int i = 0; i < GRID_SIZE; i++) {
sum += grid[i][i];
}
if (sum != magicNum) {
return false;
}
sum = 0;
for (int i = 0; i < GRID_SIZE; i++) {
sum += grid[i][GRID_SIZE - 1 - i];
}
if (sum != magicNum) {
return false;
}
return true;
}
private boolean solve(int[][] grid, int row, int col) {
if (row == GRID_SIZE && col == 0) {
return isMagicSquare(grid);
}
if (grid[row][col] != 0) {
// 当前格已经有数字,跳过
if (col == GRID_SIZE - 1) {
return solve(grid, row + 1, 0);
} else {
return solve(grid, row, col + 1);
}
} else {
// 尝试填入数字
for (int i = 1; i <= GRID_SIZE * GRID_SIZE; i++) {
grid[row][col] = i;
if (col == GRID_SIZE - 1) {
if (solve(grid, row + 1, 0)) {
return true;
}
} else {
if (solve(grid, row, col + 1)) {
return true;
}
}
grid[row][col] = 0;
}
return false;
}
}
public void generateMagicSquare() {
int[][] grid = new int[GRID_SIZE][GRID_SIZE];
solve(grid, 0, 0);
printGrid(grid);
}
private void printGrid(int[][] grid) {
for (int i = 0; i < GRID_SIZE; i++) {
for (int j = 0; j < GRID_SIZE; j++) {
System.out.print(grid[i][j] + " ");
}
System.out.println();
}
}
}
```
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