python写一个单片机竞速迷宫小车的代码
时间: 2024-12-19 21:21:21 浏览: 14
编写Python控制单片机竞速迷宫小车的代码通常涉及硬件交互、传感器读取以及路径决策算法。这里假设我们使用的是Raspberry Pi作为主控,并通过GPIO模块操控马达,同时使用超声波传感器或红外传感器检测迷宫边界。
```python
import RPi.GPIO as GPIO
import time
# 设置GPIO模式
GPIO.setmode(GPIO.BCM)
# 定义输入和输出引脚
Motor_pins = [18, 22] # 两个电机驱动引脚,根据实际情况设置
Sensor_pin = 4 # 超声波传感器引脚
ENA_PIN = 5 # ENA引脚用于启用电机
IN1_PIN = 6 # IN1引脚用于控制电机方向
# 初始化GPIO
for pin in Motor_pins + [ENA_PIN, IN1_PIN]:
GPIO.setup(pin, GPIO.OUT)
def forward(speed):
GPIO.output(ENA_PIN, True)
GPIO.output(IN1_PIN, False)
GPIO.output(Motor_pins[0], not speed)
GPIO.output(Motor_pins[1], speed)
def backward(speed):
GPIO.output(ENA_PIN, True)
GPIO.output(IN1_PIN, True)
GPIO.output(Motor_pins[0], speed)
GPIO.output(Motor_pins[1], not speed)
def stop():
GPIO.output(ENA_PIN, False)
def read_distance():
GPIO.output(Sensor_pin, GPIO.LOW) # 发出脉冲
time.sleep(0.00001)
GPIO.output(Sensor_pin, GPIO.HIGH)
start_time = time.time()
while GPIO.input(Sensor_pin) == GPIO.LOW:
pass
received_time = time.time() - start_time
distance = (received_time * 17150) / 2 # 计算距离公式
return distance
def navigate_maze():
forward_speed = 0.5 # 马达速度
min_distance = 50 # 边界安全距离
while True:
distance = read_distance()
if distance < min_distance:
print(f"前方障碍,距离{distance}mm")
turn_left(forward_speed) # 左转避免障碍
else:
continue_navigating(forward_speed) # 继续前行
def turn_left(speed):
for _ in range(3): # 可能需要多次调整角度,实际应用中可能需更复杂算法
forward(-speed)
time.sleep(0.5)
stop()
def continue_navigating(speed):
# 这里可以添加简单的前进、右转等逻辑,比如判断下一个节点
# 然后更新前进方向和速度
...
try:
navigate_maze()
except KeyboardInterrupt:
print("接收中断,清理GPIO...")
finally:
GPIO.cleanup() # 释放所有GPIO资源
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