buuctf 极客大挑战2019php
时间: 2023-09-14 17:08:49 浏览: 78
buuctf 极客大挑战2019php是指buuctf举办的一个PHP编程比赛,它是基于阿里云IoT技术平台的创新挑战赛。在该比赛中,参赛者需要利用PHP编写代码解决一系列技术难题。这些问题可能涉及到序列化、反序列化、变量值的展示等。序列化是指将对象转化为字符串的过程,而反序列化则是将字符串转化为对象的过程。在PHP中,可以使用serialize()函数进行序列化,并使用var_dump()函数进行反序列化结果的展示。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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- *1* [阿里云IoT极客创新挑战赛.pdf](https://download.csdn.net/download/weixin_38744375/11634853)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 50%"]
- *2* *3* [【BUUCTF-Web】 [极客大挑战 2019]PHP](https://blog.csdn.net/m0_51683653/article/details/126693573)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 50%"]
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