求1+1/3+1/5+

以下是两种求解1+1/3+1/5+...的方法：

方法一：Python代码

n = int(input("请输入n的值："))
sum = 0
for i in range(1, n+1):
    if i % 2 == 1:
        sum += 1/i
print("1+1/3+1/5+...的前", n, "项之和为：%.3f" % sum)

方法二：C++代码

#include <iostream>
#include <iomanip>
using namespace std;

int main() {
    int n;
    double sum = 0, x;
    cout << "Enter n: ";
    cin >> n;
    for (int i = 1; i <= n; i++) {
        x = 2 * i - 1;
        sum += 1 / x;
    }
    cout.setf(ios::fixed);
    cout << setprecision(3) << "1+1/3+1/5+...的前" << n << "项之和为：" << sum << endl;
    return 0;
}