用爬虫爬取猫眼电影榜单前100数据

好的，以下是使用Python的爬虫代码：

import requests
from bs4 import BeautifulSoup

url = 'https://maoyan.com/board/4'
headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3'
}

response = requests.get(url, headers=headers)
soup = BeautifulSoup(response.text, 'html.parser')
movies = soup.find_all('div', class_='movie-item-info')

for index, movie in enumerate(movies):
    title = movie.find('a').text
    star = movie.find('p', class_='star').text.strip()[3:]
    time = movie.find('p', class_='releasetime').text.strip()[5:]
    score = movie.find('p', class_='score').text.strip()
    print(f'排名：{index+1}')
    print(f'电影名称：{title}')
    print(f'主演：{star}')
    print(f'上映时间：{time}')
    print(f'评分：{score}')
    print('-'*60)

执行代码后，将会输出猫眼电影榜单前100的电影信息。