利用函数模板写一个函数模板，名为max_min_mean。求int数组，float数组和double数组平均值、最大值和最小值。数组大小为5，元素值任意 在main函数中输出（不要在函数中输出）

下面是一个实现 max_min_mean 函数模板的例子：

#include <iostream>
#include <algorithm>

template<typename T>
void max_min_mean(T arr[], int size, T& max, T& min, double& mean) {
    max = *std::max_element(arr, arr + size);
    min = *std::min_element(arr, arr + size);
    mean = 0;
    for (int i = 0; i < size; ++i) {
        mean += arr[i];
    }
    mean /= size;
}

int main() {
    int arr1[] = {1, 2, 3, 4, 5};
    float arr2[] = {1.5f, 2.5f, 3.5f, 4.5f, 5.5f};
    double arr3[] = {1.2, 2.3, 3.4, 4.5, 5.6};

    int max1, min1;
    double mean1;
    max_min_mean(arr1, 5, max1, min1, mean1);
    std::cout << "int array: max=" << max1 << ", min=" << min1 << ", mean=" << mean1 << std::endl;

    float max2, min2;
    double mean2;
    max_min_mean(arr2, 5, max2, min2, mean2);
    std::cout << "float array: max=" << max2 << ", min=" << min2 << ", mean=" << mean2 << std::endl;

    double max3, min3;
    double mean3;
    max_min_mean(arr3, 5, max3, min3, mean3);
    std::cout << "double array: max=" << max3 << ", min=" << min3 << ", mean=" << mean3 << std::endl;

    return 0;
}

输出结果为：

int array: max=5, min=1, mean=3
float array: max=5.5, min=1.5, mean=3.5
double array: max=5.6, min=1.2, mean=3.4