写一个贪吃蛇 c语言代码

很高兴回答您的问题。以下是一个简单的贪吃蛇 C 语言代码：

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>

#define width 20
#define height 20

int x, y, fruitX, fruitY, score, gameover;
int tailX[100], tailY[100];
int nTail;

void Setup()
{
gameover = ;
x = width / 2;
y = height / 2;
fruitX = rand() % width;
fruitY = rand() % height;
score = ;
}

void Draw()
{
system("cls");
for (int i = ; i < width + 2; i++)
printf("#");
printf("\n");

for (int i = ; i < height; i++)
{
for (int j = ; j < width; j++)
{
if (j == )
printf("#");
if (i == y && j == x)
printf("O");
else if (i == fruitY && j == fruitX)
printf("F");
else
{
int print = ;
for (int k = ; k < nTail; k++)
{
if (tailX[k] == j && tailY[k] == i)
{
printf("o");
print = 1;
}
}
if (!print)
printf(" ");
}

if (j == width - 1)
printf("#");
}
printf("\n");
}

for (int i = ; i < width + 2; i++)
printf("#");
printf("\n");
printf("Score: %d\n", score);
}

void Input()
{
if (_kbhit())
{
switch (_getch())
{
case 'a':
x--;
break;
case 'd':
x++;
break;
case 'w':
y--;
break;
case 's':
y++;
break;
case 'x':
gameover = 1;
break;
}
}
}

void Logic()
{
int prevX = tailX[];
int prevY = tailY[];
int prev2X, prev2Y;
tailX[] = x;
tailY[] = y;
for (int i = 1; i < nTail; i++)
{
prev2X = tailX[i];
prev2Y = tailY[i];
tailX[i] = prevX;
tailY[i] = prevY;
prevX = prev2X;
prevY = prev2Y;
}
switch (_getch())
{
case 'a':
x--;
break;
case 'd':
x++;
break;
case 'w':
y--;
break;
case 's':
y++;
break;
case 'x':
gameover = 1;
break;
}
if (x > width || x < || y > height || y < )
gameover = 1;
for (int i = ; i < nTail; i++)
if (tailX[i] == x && tailY[i] == y)
gameover = 1;
if (x == fruitX && y == fruitY)
{
score += 10;
fruitX = rand() % width;
fruitY = rand() % height;
nTail++;
}
}

int main()
{
Setup();
while (!gameover)
{
Draw();
Input();
Logic();
Sleep(50);
}
return ;
}