android studio 登录页面代码
时间: 2023-07-01 20:16:06 浏览: 68
以下是一个基本的 Android Studio 登录页面代码的示例:
activity_login.xml:
```xml
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:gravity="center"
android:orientation="vertical">
<EditText
android:id="@+id/username_edit_text"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="Username" />
<EditText
android:id="@+id/password_edit_text"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="Password"
android:inputType="textPassword" />
<Button
android:id="@+id/login_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Log In" />
</LinearLayout>
```
LoginActivity.java:
```java
public class LoginActivity extends AppCompatActivity {
private EditText usernameEditText;
private EditText passwordEditText;
private Button loginButton;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
usernameEditText = findViewById(R.id.username_edit_text);
passwordEditText = findViewById(R.id.password_edit_text);
loginButton = findViewById(R.id.login_button);
loginButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String username = usernameEditText.getText().toString();
String password = passwordEditText.getText().toString();
// TODO: Implement login logic here
if (username.equals("admin") && password.equals("password")) {
Intent intent = new Intent(LoginActivity.this, MainActivity.class);
startActivity(intent);
finish();
} else {
Toast.makeText(LoginActivity.this, "Invalid username or password", Toast.LENGTH_SHORT).show();
}
}
});
}
}
```
请注意,这只是一个基本示例代码,您需要根据您的需求进行更改和调整。