.求》㎡。(即求1!+2!+3!+4!+5!+6!)(while结构实现)c语言
时间: 2023-11-24 13:51:26 浏览: 28
以下是C语言使用while结构实现求1!+2!+3!+4!+5!+6!的代码:
```c
#include <stdio.h>
int main() {
int i = 1, sum = 0, factorial = 1;
while (i <= 6) {
factorial *= i;
sum += factorial;
i++;
}
printf("1!+2!+3!+4!+5!+6!=%d", sum); // 输出:1!+2!+3!+4!+5!+6!=873
return 0;
}
```
相关问题
求1!+2+!+3!+4!+5!+6!(while结构实现)
以下是使用while循环结构实现1!+2!+3!+....+6!的代码:
```python
n = 1
sum = 0
while n <= 6:
i = 1
factorial = 1
while i <= n:
factorial *= i
i += 1
sum += factorial
n += 1
print("1!+2!+3!+4!+5!+6!=", sum) # 输出:1!+2!+3!+4!+5!+6!=873
```
.求》㎡。(即求1!+2!+3!+4!+5!+6!)(while结构实现)
以下是使用while结构实现求1!+2!+3!+4!+5!+6!的Python代码:
```python
n = 1
sum = 0
while n <= 6:
i = 1
factorial = 1
while i <= n:
factorial *= i
i += 1
sum += factorial
n += 1
print(sum) # 输出:873
```
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