请用c语言，给出层序遍历序列构建二叉树的代码

很高兴与您进行交流！对于您的问题，我很乐意为您提供帮助。以下是使用 C 语言进行层序遍历序列构建二叉树的代码示例：

#include <stdio.h>
#include <stdlib.h>

struct TreeNode {
    int data;
    struct TreeNode* left;
    struct TreeNode* right;
};

// 辅助队列的定义
struct Queue {
    int front;
    int rear;
    int size;
    struct TreeNode** array;
};

// 创建一个新的队列
struct Queue* createQueue(int size) {
    struct Queue* queue = (struct Queue*)malloc(sizeof(struct Queue));
    queue->front = 0;
    queue->rear = 0;
    queue->size = size;
    queue->array = (struct TreeNode**)malloc(size * sizeof(struct TreeNode*));
    return queue;
}

// 判断队列是否为空
int isEmpty(struct Queue* queue) {
    return queue->front == queue->rear;
}

// 添加元素到队列尾部
void enqueue(struct Queue* queue, struct TreeNode* item) {
    if (queue->rear == queue->size) {
        printf("队列已满，添加元素失败\n");
        return;
    }
    queue->array[queue->rear++] = item;
}

// 从队列首部移除一个元素
struct TreeNode* dequeue(struct Queue* queue) {
    if (isEmpty(queue)) {
        printf("队列为空，移除元素失败\n");
        return NULL;
    }
    struct TreeNode* item = queue->array[queue->front++];
    return item;
}

// 通过层序遍历序列构建二叉树
struct TreeNode* createTree(int* levelOrder, int size) {
    if (size == 0) {
        return NULL;
    }
    struct TreeNode* root = (struct TreeNode*)malloc(sizeof(struct TreeNode));
    root->data = levelOrder[0];
    root->left = NULL;
    root->right = NULL;
    struct Queue* queue = createQueue(size);
    enqueue(queue, root);
    int i = 1;
    while (i < size) {
        struct TreeNode* node = dequeue(queue);
        if (i < size) {
            struct TreeNode* left = (struct TreeNode*)malloc(sizeof(struct TreeNode));
            left->data = levelOrder[i++];
            left->left = NULL;
            left->right = NULL;
            node->left = left;
            enqueue(queue, left);
        }
        if (i < size) {
            struct TreeNode* right = (struct TreeNode*)malloc(sizeof(struct TreeNode));
            right->data = levelOrder[i++];
            right->left = NULL;
            right->right = NULL;
            node->right = right;
            enqueue(queue, right);
        }
    }
    return root;
}

// 打印二叉树的层序遍历序列
void printLevelOrder(struct TreeNode* root) {
    if (root == NULL) {
        printf("二叉树为空\n");
        return;
    }
    struct Queue* queue = createQueue(100);
    enqueue(queue, root);
    printf("二叉树的层序遍历序列为：");
    while (!isEmpty(queue)) {
        struct TreeNode* node = dequeue(queue);
        printf("%d ", node->data);
        if (node->left) {
            enqueue(queue, node->left);
        }
        if (node->right) {
            enqueue(queue, node->right);
        }
    }
    printf("\n");
}

// 主函数
int main() {
    int levelOrder[] = {1, 2, 3, 4, 5, 6, 7};
    int size = sizeof(levelOrder) / sizeof(levelOrder[0]);
    struct TreeNode* root = createTree(levelOrder, size);
    printLevelOrder(root);
    return 0;
}

希望这段代码能够对您有所帮助！如果您还有其他问题需要解答，请随时向我提出。