在springboot用@Controller @ResponseBody@Autowired @PostMapping@Service@Mapper@Data实现用户登录案例
时间: 2023-10-04 19:07:36 浏览: 149
好的,下面是一个基于 Spring Boot 的用户登录案例:
1. 创建 User 实体类
```java
@Data
public class User {
private String username;
private String password;
}
```
2. 创建 UserService 接口和实现类
```java
public interface UserService {
User login(String username, String password);
}
@Service
public class UserServiceImpl implements UserService {
@Override
public User login(String username, String password) {
// 在这里校验用户名和密码是否正确,省略实现
return new User(username, password);
}
}
```
3. 创建 UserController 控制器
```java
@Controller
public class UserController {
@Autowired
private UserService userService;
@PostMapping("/login")
@ResponseBody
public String login(@RequestBody User user) {
User loginUser = userService.login(user.getUsername(), user.getPassword());
if (loginUser != null) {
return "登录成功";
} else {
return "用户名或密码错误";
}
}
}
```
4. 配置 mybatis 和数据库信息
在 application.properties 文件中添加以下配置:
```
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.datasource.url=jdbc:mysql://localhost:3306/test?useUnicode=true&characterEncoding=UTF-8&autoReconnect=true&failOverReadOnly=false&maxReconnects=10
spring.datasource.username=root
spring.datasource.password=root
mybatis.mapper-locations=classpath:mapper/*.xml
```
5. 创建 UserMapper 接口和 XML 映射文件
```java
@Mapper
public interface UserMapper {
User selectByUsernameAndPassword(@Param("username") String username, @Param("password") String password);
}
```
在 mapper 文件夹下创建 UserMapper.xml 文件,编写 SQL 语句:
```xml
<mapper namespace="com.example.demo.mapper.UserMapper">
<resultMap id="BaseResultMap" type="com.example.demo.entity.User">
<id column="username" property="username" />
<result column="password" property="password" />
</resultMap>
<select id="selectByUsernameAndPassword" resultMap="BaseResultMap">
select * from user where username=#{username} and password=#{password}
</select>
</mapper>
```
6. 编写测试代码
```java
@RunWith(SpringRunner.class)
@SpringBootTest
public class UserControllerTests {
@Autowired
private UserController userController;
@Test
public void testLogin() {
User user = new User();
user.setUsername("admin");
user.setPassword("123456");
String result = userController.login(user);
assertEquals("登录成功", result);
}
}
```
以上就是一个基于 Spring Boot 的用户登录案例的实现过程,希望对你有所帮助。
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