以提升运行速度为目的简化以下代码：delta0=[0,0,1,1,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,1,1,1,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;1,0,1,0,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,0,1,1,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,1,1,1,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,0,1,0,1,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,0,1,1,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,0,1,1,0,0,1,0,0,0,1,1,0,0,1,0,0,0,0,0,0,0,0,0,0;0,0,1,0,1,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;0,0,1,1,1,1,1,0,0,0,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0;0,0,0,1,1,0,1,0,0,0,0,0,0,0,0,1,1,0,1,0,0,0,0,0,0;0,0,0,1,0,0,1,0,0,0,0,1,0,0,1,1,0,0,1,0,0,0,0,0,0;0,0,0,0,1,0,1,0,1,1,0,0,0,0,0,0,1,0,1,0,0,0,0,0,0;0,0,0,1,1,1,1,0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,0,0,0;0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,1,0,1,1,0,1,0,0,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0;0,0,0,0,1,0,1,0,1,1,0,0,0,0,0,0,1,0,1,0,0,0,0,0,0;0,0,0,0,1,1,1,0,0,0,0,0,1,1,1,0,1,1,1,1,1,1,0,0,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,0,1,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0;0,0,0,0,0,0,1,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0;0,0,0,0,0,1,1,0,0,0,0,0,0,1,1,0,0,1,1,0,1,1,1,1,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,0,1,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0;0,0,0,0,0,0,1,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0;0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,1,1]; delta=[]; for l=1:L deltal=[]; for t=1:T deltal=[deltal;delta0(4*l-3:4*l,:)]; end delta=[delta;deltal]; end

可以使用矩阵索引和reshape函数来简化代码，如下所示：

delta = reshape(repmat(delta0,4,1),[],size(delta0,2));

首先，我们使用repmat函数将delta0的每一行复制4次，并在垂直方向上连接这些行，从而创建一个新的矩阵。然后，我们使用reshape函数将该矩阵重新构造成一个大小为28x5的矩阵。这种方法可以避免使用循环和临时变量，并且使用矩阵运算可以更快地生成delta矩阵。