输入一个1-4的数字，输出该整数对应的季度的英文单词，季度英文单词分别为：spring、summer、autumn、winrer

ChatGPT：Sure, I can help you with that. Here is the code:

def get_season(num):
    if num == 1:
        return "spring"
    elif num == 2:
        return "summer"
    elif num == 3:
        return "autumn"
    elif num == 4:
        return "winter"
    else:
        return "Invalid input. Please enter a number between 1 and 4."

number = input("Please enter a number between 1 and 4: ")
print(get_season(int(number)))

Please note that this code can only handle input values between 1 and 4, and will output an error message for any other values.

相关问题

c++输出将整数1~4转换为对应的4个季节。例如：1、2、3、4对应spring,summer,autumn,winter。输入1~4以外的数，则输出“data error”。

#include <stdio.h>

int main() {
int num;
printf("请输入1~4中的一个数字：");
scanf("%d", &num);
switch (num) {
case 1:
printf("spring\n");
break;
case 2:
printf("summer\n");
break;
case 3:
printf("autumn\n");
break;
case 4:
printf("winter\n");
break;
default:
printf("data error\n");
break;
}
return 0;
}

输入 输入两个整数，分别表示年和月，以“-”分隔。 输出 一句英文，这是某某年的春天（夏天/秋天/冬天）。即：This is spring of XX(某某年)

这是一个简单的Python程序示例，用于根据输入的年份和月份判断并输出相应的季节：

def get_season(year, month):
    months = {
        '01': 'January', '02': 'February',
        '03': 'March', '04': 'April',
        '05': 'May', '06': 'June',
        '07': 'July', '08': 'August',
        '09': 'September', '10': 'October',
        '11': 'November', '12': 'December'
    }
    
    if month in [3, 4, 5]:
        season = "spring"
    elif month in [6, 7, 8]:
        season = "summer"
    elif month in [9, 10, 11]:
        season = "autumn"
    else:
        season = "winter"

    return f"This is {season} of {year}"

# 示例输入
input_str = input("请输入年份和月份，格式为：YYYY-MM: ")
year, month = map(int, input_str.split('-'))

# 调用函数
output = get_season(year, month)
print(output)